题目

类型：Math
难度：简单

解题思路

代码

public String toHex(int num) {
        if (num == 0) {
            return "0";
        }
        StringBuffer sb = new StringBuffer();
        for (int i = 7; i >= 0; i --) {
            int val = (num >> (4 * i)) & 0xf;
            if (sb.length() > 0 || val > 0) {
                char digit = val < 10 ? (char) ('0' + val) : (char) ('a' + val - 10);
                sb.append(digit);
            }
        }
        return sb.toString();
}