题目

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建表语句

  1. drop table if exists exam_record;
  2. CREATE TABLE exam_record (
  3. id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',
  4. uid int NOT NULL COMMENT '用户ID',
  5. exam_id int NOT NULL COMMENT '试卷ID',
  6. start_time datetime NOT NULL COMMENT '开始时间',
  7. submit_time datetime COMMENT '提交时间',
  8. score tinyint COMMENT '得分'
  9. )CHARACTER SET utf8 COLLATE utf8_general_ci;
  10. INSERT INTO exam_record(uid,exam_id,start_time,submit_time,score) VALUES
  11. (1001, 9001, '2020-01-02 09:01:01', '2020-01-02 09:21:01', 80),
  12. (1001, 9001, '2021-05-02 10:01:01', '2021-05-02 10:30:01', 81),
  13. (1001, 9001, '2021-06-02 19:01:01', '2021-06-02 19:31:01', 84),
  14. (1001, 9002, '2021-09-05 19:01:01', '2021-09-05 19:40:01', 89),
  15. (1001, 9001, '2021-09-02 12:01:01', null, null),
  16. (1001, 9002, '2021-09-01 12:01:01', null, null),
  17. (1002, 9002, '2021-02-02 19:01:01', '2021-02-02 19:30:01', 87),
  18. (1002, 9001, '2021-05-05 18:01:01', '2021-05-05 18:59:02', 90),
  19. (1003, 9001, '2021-02-06 12:01:01', null, null),
  20. (1003, 9001, '2021-09-07 10:01:01', '2021-09-07 10:31:01', 89),
  21. (1004, 9001, '2021-09-06 12:01:01', null, null);

解题思路

用例:

drop table if exists exam_record;
CREATE TABLE  exam_record (
id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',
uid int NOT NULL COMMENT '用户ID',
exam_id int NOT NULL COMMENT '试卷ID',
start_time datetime NOT NULL COMMENT '开始时间',
submit_time datetime COMMENT '提交时间',
score tinyint COMMENT '得分'
)CHARACTER SET utf8 COLLATE utf8_general_ci;


INSERT INTO exam_record(uid,exam_id,start_time,submit_time,score) VALUES
(1001, 9001, '2020-01-02 09:01:01', '2020-01-02 09:21:01', 80),
(1001, 9003, '2021-05-02 10:01:01', '2021-05-02 10:30:01', 81),
(1002, 9002, '2021-09-02 12:01:01', null, null),
(1002, 9003, '2021-09-01 12:01:01', null, null),
(1002, 9001, '2021-02-02 19:01:01', '2021-02-02 19:30:01', 87),
(1003, 9002, '2021-02-06 12:01:01', null, null),
(1003, 9001, '2021-09-07 10:01:01', '2021-09-07 10:31:01', 89),
(1004, 9003, '2021-09-06 12:01:01', null, null);

错误示范

select count(id) as total_pv,
count(submit_time) as complete_pv,
count(DISTINCT exam_id) as complete_exam_cnt
from exam_record;

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SQL代码

SELECT
COUNT(start_time) as total_pv, #有开始作答时间可视为一次作答
COUNT(submit_time) as complete_pv,#有交卷时间可视为完成一次作答
count(distinct exam_id and score is not null)
as complete_exam_cnt#将试卷去重,同时将筛选完成的试卷
from exam_record;