spring如何发post或get请求

问题

@RequestMapping(value = { "/lego/mobileMonitor/deviceLogDiagnose.json" }, method = { RequestMethod.POST, RequestMethod.GET })
public void deviceLogDiagnoseTrigger(ModelMap model, @RequestParam(value = "app", required = false) String app,
   @RequestParam(value = "platform", required = true) String platform,
   @RequestParam(value = "userId", required = true) String userId,
   @RequestParam(value = "description", required = false) String description,
   @RequestParam(value = "clientTime", required = true) String clientTime)

以上写法只支持get请求，不支持post，虽然写了post，但post不生效

如何写呢

场景方法：https://www.cnblogs.com/xiaoxi/p/5695783.html

一般不建议一个请求既支持post请求，也支持get请求

常见post请求的写法

@RequestMapping(value = "/duplicate.json", method = RequestMethod.POST)
public Object duplicate(@RequestBody JSONObject json) {
  PreCheck.isPresent(json, "scName", "scCode", "desc", "condition", "filter", "admins");
  String scName = json.getString("scName");
  String scCode = json.getString("scCode");
  String desc = json.getString("desc");
  String condition = json.getString("condition");
}

从参数json中再解析出所需的参数

或通过HttpServletRequest接收(这种写法也支持get)

@RequestMapping("/addUser2")
public String addUser2(HttpServletRequest request) {
    String username=request.getParameter("username");
    String password=request.getParameter("password");
    System.out.println("username is:"+username);
    System.out.println("password is:"+password);
    return "demo/index";
}

常见get请求的写法

/**
`* 1.直接把表单的参数写在Controller相应的方法的形参中
 * @param username
* @param password
* @return
*/
@RequestMapping("/addUser1")
public String addUser1(String username,String password) {
   System.out.println("username is:"+username);
   System.out.println("password is:"+password);
   return "demo/index";
}`

注意这种写法默认参数都必传。如果参数不必传，使用@Requestparam注解