C 程序：通过将结构传递给函数来相加复数

原文： https://www.programiz.com/cpp-programming/examples/complex-number-add

该程序将两个复数作为结构并通过使用函数将它们相加。

要理解此示例，您应该了解以下 C++ 编程主题：

• C++ 结构
• C++ 结构和函数

示例：相加两个复数的源代码

// Complex numbers are entered by the user
#include <iostream>
using namespace std;
typedef struct complex
{
    float real;
    float imag;
} complexNumber;
complexNumber addComplexNumbers(complex, complex);
int main()
{
    complexNumber n1, n2, temporaryNumber;
    char signOfImag;
    cout << "For 1st complex number," << endl;
    cout << "Enter real and imaginary parts respectively:" << endl;
    cin >> n1.real >> n1.imag;
    cout << endl << "For 2nd complex number," << endl;
    cout << "Enter real and imaginary parts respectively:" << endl;
    cin >> n2.real >> n2.imag;
    signOfImag = (temporaryNumber.imag > 0) ? '+' : '-';
    temporaryNumber.imag = (temporaryNumber.imag > 0) ? temporaryNumber.imag : -temporaryNumber.imag; 
    temporaryNumber = addComplexNumbers(n1, n2);    
    cout << "Sum = "  << temporaryNumber.real << temporaryNumber.imag << "i";
    return 0;
}
complexNumber addComplexNumbers(complex n1,complex n2)
{
      complex temp;
      temp.real = n1.real+n2.real;
      temp.imag = n1.imag+n2.imag;
      return(temp);
}

输出

Enter real and imaginary parts respectively:
3.4
5.5
For 2nd complex number,
Enter real and imaginary parts respectively:
-4.5
-9.5
Sum = -1.1-4i

在问题中，用户输入的两个复数存储在结构n1和n2中。

这两个结构传递给addComplexNumbers()函数，该函数计算总和并将结果返回给main()函数。

最后，通过main()函数显示总和。