原文: https://www.programiz.com/c-programming/examples/matrix-multiplication
在此示例中,您将学习将两个矩阵相乘并使用用户定义的函数进行显示。
要理解此示例,您应该了解以下 C 编程主题:
该程序要求用户输入两个矩阵的大小(行和列)。
为了将两个矩阵相乘,第一个矩阵的列数应等于第二个矩阵的行数。
下面的程序要求两个矩阵的行数和列数,直到满足上述条件。
然后,执行两个矩阵的相乘,结果显示在屏幕上。
为此,我们创建了三个函数:
enterData()- 从用户那里获取矩阵元素。multiplyMatrices()- 将两个矩阵相乘。display()- 显示相乘后的结果矩阵。
通过将矩阵传递给函数来相乘
#include <stdio.h>void enterData(int first[][10], int second[][10], int r1, int c1, int r2, int c2);void multiplyMatrices(int first[][10], int second[][10], int multResult[][10], int r1, int c1, int r2, int c2);void display(int mult[][10], int r1, int c2);int main() {int first[10][10], second[10][10], mult[10][10], r1, c1, r2, c2;printf("Enter rows and column for the first matrix: ");scanf("%d %d", &r1, &c1);printf("Enter rows and column for the second matrix: ");scanf("%d %d", &r2, &c2);// Taking input until columns of the first matrix is equal to the rows of the second matrixwhile (c1 != r2) {printf("Error! Enter rows and columns again.\n");printf("Enter rows and columns for the first matrix: ");scanf("%d%d", &r1, &c1);printf("Enter rows and columns for the second matrix: ");scanf("%d%d", &r2, &c2);}// Function to take matrices dataenterData(first, second, r1, c1, r2, c2);// Function to multiply two matrices.multiplyMatrices(first, second, mult, r1, c1, r2, c2);// Function to display resultant matrix after multiplication.display(mult, r1, c2);return 0;}void enterData(int first[][10], int second[][10], int r1, int c1, int r2, int c2) {printf("\nEnter elements of matrix 1:\n");for (int i = 0; i < r1; ++i) {for (int j = 0; j < c1; ++j) {printf("Enter a%d%d: ", i + 1, j + 1);scanf("%d", &first[i][j]);}}printf("\nEnter elements of matrix 2:\n");for (int i = 0; i < r2; ++i) {for (int j = 0; j < c2; ++j) {printf("Enter b%d%d: ", i + 1, j + 1);scanf("%d", &second[i][j]);}}}void multiplyMatrices(int first[][10], int second[][10], int mult[][10], int r1, int c1, int r2, int c2) {// Initializing elements of matrix mult to 0.for (int i = 0; i < r1; ++i) {for (int j = 0; j < c2; ++j) {mult[i][j] = 0;}}// Multiplying first and second matrices and storing in mult.for (int i = 0; i < r1; ++i) {for (int j = 0; j < c2; ++j) {for (int k = 0; k < c1; ++k) {mult[i][j] += first[i][k] * second[k][j];}}}}void display(int mult[][10], int r1, int c2) {printf("\nOutput Matrix:\n");for (int i = 0; i < r1; ++i) {for (int j = 0; j < c2; ++j) {printf("%d ", mult[i][j]);if (j == c2 - 1)printf("\n");}}}
输出
Enter rows and column for the first matrix: 23Enter rows and column for the second matrix: 32Enter elements of matrix 1:Enter a11: 3Enter a12: -2Enter a13: 5Enter a21: 3Enter a22: 0Enter a23: 4Enter elements of matrix 2:Enter b11: 2Enter b12: 3Enter b21: -9Enter b22: 0Enter b31: 0Enter b32: 4Output Matrix:24 296 25
