思路:
通法就是递归,其他方法暂不考虑
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
var countNodes = function(root) {
let result = 0
let nodes = data => {
if (data) {
nodes(data.left)
nodes(data.right)
result++
}
}
nodes(root)
return result
};