922. 按奇偶排序数组 II🔖暴力

• https://leetcode-cn.com/problems/sort-array-by-parity-ii/

思路：我特喵的直接暴力解法

/**
 * @param {number[]} nums
 * @return {number[]}
 */
var sortArrayByParityII = function(nums) {
    let arr = []
    let arr_ou = []
    let arr_ji = []
    nums.forEach(data => {
        data % 2 === 0 ? arr_ou.push(data) : arr_ji.push(data)
    })
    for (let i = 0; i<arr_ji.length ;i++) {
        arr[i * 2] = arr_ou[i]
        arr[i * 2 + 1] = arr_ji[i]
    }
    return arr
};