给你一个整数 n ,请你生成并返回所有由 n 个节点组成且节点值从 1 到 n 互不相同的不同 二叉搜索树 。可以按 任意顺序 返回答案。
示例 1:
输入:n = 3
输出:[[1,null,2,null,3],[1,null,3,2],[2,1,3],[3,1,null,null,2],[3,2,null,1]]
示例 2:
输入:n = 1
输出:[[1]]
/*** Definition for a binary tree node.* function TreeNode(val, left, right) {* this.val = (val===undefined ? 0 : val)* this.left = (left===undefined ? null : left)* this.right = (right===undefined ? null : right)* }*//*** @param {number} n* @return {TreeNode[]}*/var generateTrees = function (n) {if (n === 0) return [];const build = (lo, hi) => {let res = [];if (lo > hi) {res.push(null)return res;}// 1、穷举所有节点for (let i = lo; i <= hi; i += 1) {// 递归所有合法左右子树let leftTree = build(lo, i - 1);let rightTree = build(i + 1, hi);// 穷举组合for (let left of leftTree) {for (let right of rightTree) {// i 作为根节点 root 的值let root = new TreeNode(i);root.left = left;root.right = right;res.push(root);}}}return res;}return build(1, n)};

