给你两个字符串:ransomNote 和 magazine ,判断 ransomNote 能不能由 magazine 里面的字符构成。
如果可以,返回 true ;否则返回 false 。
magazine 中的每个字符只能在 ransomNote 中使用一次。
示例 1:
输入:ransomNote = “a”, magazine = “b”
输出:false
示例 2:
输入:ransomNote = “aa”, magazine = “ab”
输出:false
示例 3:
输入:ransomNote = “aa”, magazine = “aab”
输出:true
/*** @param {string} ransomNote* @param {string} magazine* @return {boolean}*/var canConstruct = function (ransomNote, magazine) {const map = new Map();for (str of magazine) {map.set(str, (map.get(str) || 0) + 1)}for (let i = 0; i < ransomNote.length; i += 1) {if (map.has(ransomNote[i])) {map.set(ransomNote[i], (map.get(ransomNote[i]) - 1))if (map.get(ransomNote[i]) < 0) {return false}} else {return false}}return map.size > 0};

