对角阵
- 提取矩阵的对角线元素
- 构造对角阵
先建立矩阵A,然后将A的第一行矩阵乘以1,第二行乘以2,…,第五行乘以5
>> A = [7,0,1,0,5; 3,5,7,4,1; 4,0,3,0,2; 1,1,9,2,3; 1,8,5,2,9]
A =
7 0 1 0 5
3 5 7 4 1
4 0 3 0 2
1 1 9 2 3
1 8 5 2 9
>> D = diag(1:5);
>> D * A
ans =
7 0 1 0 5
6 10 14 8 2
12 0 9 0 6
4 4 36 8 12
5 40 25 10 45
>> D = diag(1:5);
>> D * A
ans =
7 0 3 0 25
3 10 21 16 5
4 0 9 0 10
1 2 27 8 15
1 16 15 8 45
对角阵
- 上三角阵
>> triu(ones(4), -1)
ans =
1 1 1 1
1 1 1 1
0 1 1 1
0 0 1 1
- 下三角阵
矩阵的转置
>> A = [1,3; 3+4i, 1-2i]
A =
1 + 0i 3 + 0i
3 + 4i 1 - 2i
>> A.'
ans =
1 + 0i 3 + 4i
3 + 0i 1 - 2i
>> A'
ans =
1 + 0i 3 - 4i
3 + 0i 1 + 2i
矩阵的旋转
>> A = [1,3,2; -3,2,1; 4,1,2]
A =
1 3 2
-3 2 1
4 1 2
>> rot90(A)
ans =
2 1 2
3 2 1
1 -3 4
>> rot90(A, 2)
ans =
2 1 4
1 2 -3
2 3 1
矩阵的翻转
验证魔方阵的主对角线、副对角线元素之和相等
>> A = magic(5);
>> D1 = diag(A);
>> sum(D1)
ans =
65
>> B = flipud(A);
>> D2 = diag(B);
>> sum(D2)
ans =
65
矩阵的求逆
>> A = [1,2,3; 1,4,9; 1,8,27]
A =
1 2 3
1 4 9
1 8 27
>> b = [5;-2;6]
b =
5
-2
6
>> x = inv(A) * b
x =
23
-29/2
11/3
>> x = A\b
x =
23
-29/2
11/3