第二大题 改错题

最后大题40分 程序填空题

1. 控制台画图 ```cpp

   include

   include

   include

   include

   using namespace std; class Timer { private: int sec; int x,y;//move int c;//key clock_t t1,t2,t3; public: Timer() {

    sec=0;
    x=30;y=10;
    c=0;

   //—————————————————————

//————————————————————— } void gotoxy(int x,int y) { HANDLE h;//句柄,对象的索引 COORD c;//结构体,坐标值 c.X=x; c.Y=y; h=GetStdHandle(STD_OUTPUT_HANDLE); SetConsoleCursorPosition(h,c); } void draw() { gotoxy(x,y); cout<1000) { //—————————————————————

//————————————————————— t1=clock(); } } void key() { if(clock()-t2>50) { if(GetAsyncKeyState(VK_ESCAPE)) exit(0); if(GetAsyncKeyState(VK_UP)) c=1; if(GetAsyncKeyState(VK_DOWN)) c=2; if(GetAsyncKeyState(VK_LEFT)) c=3; if(GetAsyncKeyState(VK_RIGHT)) c=4; if(GetAsyncKeyState(VK_SPACE)) c=5; t2=clock(); } } void move1() { if(clock()-t3>50) { erase(); switch(c) { case 1:y=y<0?0:y-1;break; case 2:y=y>24?24:y+1;break; case 3:x=x<0?0:x-1;break; case 4:x=x>78?78:x+1;break; case 5:sec=0;break; } draw(); c=0; t3=clock(); } } void move() { while(true) { timer(); key(); move1(); } } };

int main() { Timer t; t.move(); return 0; }

2. 运算符重载
重载"+"运算符，两个线段的顶点坐标分别相加；重载“<<”运算符，输出对象中的数据
```cpp
#include <iostream>
using namespace std;
class point
{
protected:
    int x1,y1;
public:
    point(int xx1,int yy1)
    {
        x1=xx1;y1=yy1;
    }
};
class line:public point
{
protected:
    int x2,y2;
public:
    line(int xx1,int yy1,int xx2,int yy2):point(xx1,yy1)
    {
        x2=xx2;y2=yy2;
    }
    void display()
    {
        cout<<"x1="<<x1<<endl;
        cout<<"y1="<<y1<<endl;
        cout<<"x2="<<x2<<endl;
        cout<<"y2="<<y2<<endl;
    }
    line operator +(line L2)//坐标相加 
    {
//------------------------------------------
//------------------------------------------
        temp.x1=x1+L2.x1;
        temp.y1=y1+L2.y1;
        temp.x2=x2+L2.x2;
        temp.y2=y2+L2.y2;
        return temp;
    }
    friend ostream& operator<<(ostream& os,line a)
    {
//------------------------------------------
//------------------------------------------
        return os;
    }
};
int main()
{
    line L1(1,2,3,4);
    line L2(5,6,7,8);
    cout<<L1+L2;
    return 0;
}

1. 从命令行读入命令

输入三次密码，输入密码时显示为“*”。（提示：用getch（）函数无回显输入单个字符）

#include <iostream>
#include <string>
#include <conio.h>
using namespace std;
class Password
{
private:
    string password;
    int times;
public:
    Password(string ss,int nn)
    {
    }
    string input1()
    {
        string temp;
        char c;
        cout<<"input password:";
        while(true)
        {
        }
        cout<<endl;
        return temp;
    }
    void input2()
    {
        string temp;
        while(true)
        {
            temp=input1();
            if(temp==password)
            {
                cout<<"密码正确！"<<endl;
                //此处进行正常操作
                break;
            }
            else
            {
                cout<<"密码不正确！"<<endl;
                --times;
                if(times<=0)
                {
                    cout<<"输入错误，系统已退出！";
                    break;
                } 
            }
        }
    }    
};
int main()
{
    Password p("123456",3);
    p.input2();
    return 0;
}

1. 文件操作

文本文件”04-1.txt”每一行的格式为“学号 姓名 成绩”。将文本文件的每一行作为单个元素压入容器。从键盘输入姓名，从容器中查找并显示该姓名的学生信息（学号 姓名 成绩）

#include <iostream>
#include <vector>
#include <string>
#include <fstream>
#include <algorithm>
using namespace std;
struct A
{
    string s;
    bool operator==(string name)
    {
    }
};
class Score
{
private:
        vector<A>a;
        vector<A>::iterator p;
public:
    Score()
    {
        string s;
        A temp;
        ifstream f("04-1.txt",ios::in);
        if(f)
        {
            while(!f.eof())
            {
                getline(f,s);
                temp.s=s;
                a.push_back(temp);
            }
        }
    }
    void find_v()
    {
        string name;
        cout<<"input name:";
        cin>>name;
        p=find(a.begin(),a.end(),name);
        if(p!=a.end())
            cout<<p->s<<endl;
    }
};
int main()
{
    Score s;
    s.find_v();
    return 0;
}

1. 文件操作

文本文件”04-2.txt”每行的格式为“学号-姓名-成绩”。将每行作为容器的一个元素（结构体类型）读入vector容器中。将所有记录按照成绩由高到低的顺序进行排序，显示所有记录。按学号查找一个记录并显示。

#include <iostream>
#include <vector>
#include <string>
#include <fstream>
#include <algorithm>
using namespace std;
struct A
{
    string number;
    string name;
    string score;
    bool operator==(string s)
    {
    }
};
class Score
{
private:
        vector<A>a;
        vector<A>::iterator p;
public:
    Score()
    {
        string s,s1,s2,s3;
        int n1,n2;
        A temp;
        ifstream f("04-2.txt",ios::in);
        if(f)
        {
            while(!f.eof())
            {
                getline(f,s);
                temp.number=s1;
                temp.score=s3;
                temp.name=s2;
                temp.score=s3;
                a.push_back(temp);
            }
        }
    }
    static bool sort1(A a1,A a2)
    {
        return a1.score>a2.score;
    }
    void browse()
    {
        for(p=a.begin();p!=a.end();++p)
        {
            cout<<p->number<<"-"
                <<p->name<<"-"
                <<p->score<<endl;
        }
    }
    void sort_v()
    {
        sort(a.begin(),a.end(),sort1);
    }
    void find_v()
    {
        string number;
        cout<<"input number:";
        cin>>number;
        p=find(a.begin(),a.end(),number);
        if(p!=a.end())
        {
            cout<<p->number<<"-"
                <<p->name<<"-"
                <<p->score<<endl;
        }
    }
};
int main()
{
    Score s;
    s.sort_v();
    s.browse();
    s.find_v();
    return 0;
}