题目
Given an array arr of positive integers sorted in a strictly increasing order, and an integer k.
Find the kth positive integer that is missing from this array.
Example 1:
Input: arr = [2,3,4,7,11], k = 5Output: 9Explanation: The missing positive integers are [1,5,6,8,9,10,12,13,...]. The 5th missing positive integer is 9.
Example 2:
Input: arr = [1,2,3,4], k = 2Output: 6Explanation: The missing positive integers are [5,6,7,...]. The 2nd missing positive integer is 6.
Constraints:
1 <= arr.length <= 10001 <= arr[i] <= 10001 <= k <= 1000arr[i] < arr[j]for1 <= i < j <= arr.length
题意
在一个严格递增的正整数数组中找到第k个缺失的正整数。
思路
直接从1开始遍历找即可。
代码实现
Java
class Solution {public int findKthPositive(int[] arr, int k) {int ans = -1;int i = 0, j = 1;while (k != 0) {if (i < arr.length && j == arr[i]) {i++;} else {ans = j;k--;}j++;}return ans;}}
