题目

Given an array arr of positive integers sorted in a strictly increasing order, and an integer k.

Find the kth positive integer that is missing from this array.

Example 1:

  1. Input: arr = [2,3,4,7,11], k = 5
  2. Output: 9
  3. Explanation: The missing positive integers are [1,5,6,8,9,10,12,13,...]. The 5th missing positive integer is 9.

Example 2:

  1. Input: arr = [1,2,3,4], k = 2
  2. Output: 6
  3. Explanation: The missing positive integers are [5,6,7,...]. The 2nd missing positive integer is 6.

Constraints:

  • 1 <= arr.length <= 1000
  • 1 <= arr[i] <= 1000
  • 1 <= k <= 1000
  • arr[i] < arr[j] for 1 <= i < j <= arr.length

题意

在一个严格递增的正整数数组中找到第k个缺失的正整数。

思路

直接从1开始遍历找即可。


代码实现

Java

  1. class Solution {
  2. public int findKthPositive(int[] arr, int k) {
  3. int ans = -1;
  4. int i = 0, j = 1;
  5. while (k != 0) {
  6. if (i < arr.length && j == arr[i]) {
  7. i++;
  8. } else {
  9. ans = j;
  10. k--;
  11. }
  12. j++;
  13. }
  14. return ans;
  15. }
  16. }