题目
Given an integer n, return _true_ if it is a power of three. Otherwise, return _false_.
An integer n is a power of three, if there exists an integer x such that n == 3x.
Example 1:
Input: n = 27Output: true
Example 2:
Input: n = 0Output: false
Example 3:
Input: n = 9Output: true
Example 4:
Input: n = 45Output: false
Constraints:
-2^31 <= n <= 2^31 - 1
Follow up: Could you solve it without loops/recursion?
题意
判断一个整数是不是3的幂。
思路
比较直接的就迭代去除即可。
O(1)方法:在Integer范围内,3的最大幂是3^19=1162261467,且其因数只有3的幂次,那么只要n是1162261467的因数,则n一定是3的幂次。
代码实现
Java
迭代
class Solution {public boolean isPowerOfThree(int n) {if (n <= 0) return false;while (n > 1) {if (n % 3 != 0) return false;n /= 3;}return true;}}
数学计算
class Solution {public boolean isPowerOfThree(int n) {return n > 0 && 1162261467 % n == 0;}}
