题目
Note: This is a companion problem to the System Design problem: Design TinyURL-System/).
TinyURL is a URL shortening service where you enter a URL such as [https://leetcode.com/problems/design-tinyurl](https://leetcode.com/problems/design-tinyurl) and it returns a short URL such as [http://tinyurl.com/4e9iAk](http://tinyurl.com/4e9iAk).
Design the encode and decode methods for the TinyURL service. There is no restriction on how your encode/decode algorithm should work. You just need to ensure that a URL can be encoded to a tiny URL and the tiny URL can be decoded to the original URL.
题意
设计一个能将长URL和短URL互相转换的功能。
思路
无特定方法。
代码实现
Java
public class Codec {private Map<String, String> toLong = new HashMap<>();private Map<String, String> toShort = new HashMap<>();private String pool = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";private Random random = new Random();// Encodes a URL to a shortened URL.public String encode(String longUrl) {String suffix = randomSuffix(5);if (toShort.containsKey(longUrl)) {suffix = toShort.get(longUrl);} else {while (suffix == null || toLong.containsKey(suffix)) {suffix = randomSuffix(5);}toLong.put(suffix, longUrl);toShort.put(longUrl, suffix);}return "http://tinyurl.com/" + suffix;}// Decodes a shortened URL to its original URL.public String decode(String shortUrl) {return toLong.get(shortUrl.split("/", 4)[3]);}private String randomSuffix(int len) {StringBuilder sb = new StringBuilder();for (int i = 0; i < len; i++) {sb.append(pool.charAt(random.nextInt(62)));}return sb.toString();}}
