Given a m * n matrix of distinct numbers, return all lucky numbers in the matrix in any order.
A lucky number is an element of the matrix such that it is the minimum element in its row and maximum in its column.
Example 1:
Input: matrix = [[3,7,8],[9,11,13],[15,16,17]]Output: [15]Explanation: 15 is the only lucky number since it is the minimum in its row and the maximum in its column
Example 2:
Input: matrix = [[1,10,4,2],[9,3,8,7],[15,16,17,12]]Output: [12]Explanation: 12 is the only lucky number since it is the minimum in its row and the maximum in its column.
Example 3:
Input: matrix = [[7,8],[1,2]]Output: [7]
Constraints:
m == mat.lengthn == mat[i].length1 <= n, m <= 501 <= matrix[i][j] <= 10^5.- All elements in the matrix are distinct.
题意
在矩阵中,如果一个数既是它所在行的最小值,又是它所在列的最大值,则称这个数为幸运数。找到矩阵中所有的幸运数。
思路
每次先找到一行的最小值,再判断它是不是所在列的最大值。
代码实现
class Solution {public List<Integer> luckyNumbers (int[][] matrix) {List<Integer> ans = new ArrayList<>();if (matrix.length == 0) {return ans;}for (int i = 0; i < matrix.length; i++) {// 找到行的最小值int min = Integer.MAX_VALUE;int pos = 0;for (int j = 0; j < matrix[0].length; j++) {if (matrix[i][j] < min) {min = matrix[i][j];pos = j;}}// 判断是不是列的最大值boolean flag = true;for (int j = 0; j < matrix.length; j++) {if (matrix[j][pos] > min) {flag = false;break;}}if (flag) {ans.add(min);}}return ans;}}
