给定一棵二叉树,想象自己站在它的右侧,按照从顶部到底部的顺序,返回从右侧所能看到的节点值。
示例:
输入: [1,2,3,null,5,null,4]输出: [1, 3, 4]解释:1 <---/ \2 3 <---\ \5 4 <---
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    vector<int> rightSideView(TreeNode* root) {
        vector<int> res;
        if(root == NULL) return res;
        queue<TreeNode*> q;
        q.push(root);
        while(!q.empty()){
            int levelSize = q.size();
            res.push_back(q.back()->val);
            for(int i = 0; i< levelSize;i++){
                TreeNode* cur = q.front();
                q.pop();
                if(cur->left) q.push(cur->left);
                if(cur->right) q.push(cur->right);
            }          
        }
        return res;
    }
};
                    