给定一棵二叉树,想象自己站在它的右侧,按照从顶部到底部的顺序,返回从右侧所能看到的节点值。
    示例:

    1. 输入: [1,2,3,null,5,null,4]
    2. 输出: [1, 3, 4]
    3. 解释:
    4. 1 <---
    5. / \
    6. 2 3 <---
    7. \ \
    8. 5 4 <---
    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
        vector<int> rightSideView(TreeNode* root) {
            vector<int> res;
            if(root == NULL) return res;
            queue<TreeNode*> q;
            q.push(root);
            while(!q.empty()){
                int levelSize = q.size();
                res.push_back(q.back()->val);
                for(int i = 0; i< levelSize;i++){
                    TreeNode* cur = q.front();
                    q.pop();
                    if(cur->left) q.push(cur->left);
                    if(cur->right) q.push(cur->right);
                }          
            }
            return res;
    
        }
    };