给你一个二叉树,请你返回其按 层序遍历 得到的节点值。 (即逐层地,从左到右访问所有节点)。

    示例:
    二叉树:[3,9,20,null,null,15,7],

    1. 3
    2. / \
    3. 9 20
    4. / \
    5. 15 7

    返回其层次遍历结果:

    [
      [3],
      [9,20],
      [15,7]
    ]
    
    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
        vector<vector<int>> levelOrder(TreeNode* root) {
            vector<vector<int>> res;
            if(root == NULL){
                return res;
            }
            queue<TreeNode*> q;
            q.push(root);
            while(!q.empty()){
                int levelCurrentSize = q.size();
                res.push_back(vector<int>());
                for(int i =0;i<levelCurrentSize;i++){
                    TreeNode* cur = q.front();
                    q.pop();
                    res.back().push_back(cur->val);
                    if(cur->left){
                        q.push(cur->left);
                    }
                    if(cur->right){
                        q.push(cur->right);
                    }
                }
            }
            return res;
    
        }
    };