【问题】8x8的矩阵,皇后所占的那一列、一竖都不能有其他皇后
链接:https://baike.baidu.com/item/八皇后问题/11053477?fr=aladdin#1

#include<stdio.h>int count=0;//统计一共有几种int notDanger(int row,int j,int (*chess)[8]) {int i,k,flag1=0,flag2=0,flag3=0,flag4=0,flag5=0;//判断竖方向for (i=0; i<8; i++) {if ( chess[i][j] !=0 ) {flag1 = 1;break;}}//判断左上方for (i=row,k=j; i>=0&&k>=0; i--,k--) {if (chess[i][k]!=0) {flag2 = 1;break;}}//判断右下方for (i=row,k=j; i<8&&k<8; i++,k++) {if (chess[i][k]!=0) {flag3 = 1;break;}}//判断右上方for (i=row,k=j; i>=0&&k<8; i--,k++) {if (chess[i][k]!=0) {flag4 = 1;break;}}//左下方for (i=row,k=j; i<8&&k>0; i++,k--) {if (chess[i][k]!=0) {flag5 = 1;break;}}if (flag1 || flag2 || flag3 ||flag4 ||flag5)return 0;elsereturn 1;}//row起始行 n列数 (*chess)[8]指向棋盘每一行的指针void eightQueen(int row,int n,int (*chess)[8] ) {int chess2[8][8],i,j;for (i=0; i<8; i++) {for (j=0; j<8; j++) {chess2[i][j]=chess[i][j];}}if (8 == row) {printf("第%d种\n",++count);for (i=0; i<8; i++) {for (j=0; j<8; j++) {printf("%d",chess2[i][j]);}printf("\n");}printf("\n");}else {//判断这个位置是否有危险//如果没有危险,继续往下for (j=0; j<n; j++) {if (notDanger(row,j,chess)) {//判断是否危险for(i=0; i<8; i++) {*(*(chess2+row)+i)=0;}*(*(chess2+row)+j)=1;eightQueen(row+1,n,chess2);}}}}int main() {int chess[8][8],i,j;for (i=0; i<8; i++) {for (j=0; j<8; j++) {chess[i][j]=0;}}eightQueen(0,8,chess);printf("总共有解决方法%d",count);return 0;}
