为了避免用户误触返回按钮而导致APP退出,在很多APP中都拦截了用户点击返回键的按钮,然后进行一些防误触判断,比如当用户在某一个时间段内点击两次时,才会认为用户是要退出(而非误触)。Flutter中可以通过WillPopScope 来实现返回按钮拦截,我们看看 WillPopScope 的默认构造函数:
const WillPopScope({...@required WillPopCallback onWillPop,@required Widget child})
- onWillPop 是一个回调函数,我们需要提供这个回调来决定是否退出。当用户点击返回按钮时被调用(包括导航返回按钮及Android物理返回按钮)。该回调需要返回一个Future对象,如果返回的Future最终值为:
- false,则当前路由不出栈(不会返回);
- true,当前路由出栈退出。
示例
为了防止用户误触返回键退出,我们拦截返回事件。
当用户在1秒内点击两次返回按钮时,则退出;如果间隔超过1秒则不退出,并重新记时。代码如下:
import 'package:flutter/material.dart';// import 'dart:math' as math;void main() => runApp(new MyApp());class MyApp extends StatelessWidget {@overrideWidget build(BuildContext context) {return MaterialApp(debugShowCheckedModeBanner: false,title: 'WillPopScopeTestRoute',theme: ThemeData(primarySwatch: Colors.blue,),home: Scaffold(// appBar: AppBar(title: Text("滚动监听")),body: WillPopScopeTestRoute(),));}}class WillPopScopeTestRoute extends StatefulWidget {@overrideWillPopScopeTestRouteState createState() {return new WillPopScopeTestRouteState();}}class WillPopScopeTestRouteState extends State<WillPopScopeTestRoute> {DateTime _lastPressedAt; //上次点击时间@overrideWidget build(BuildContext context) {return new WillPopScope(onWillPop: () async {if (_lastPressedAt == null ||DateTime.now().difference(_lastPressedAt) >Duration(seconds: 1)) {_lastPressedAt = DateTime.now(); //两次点击间隔超过1秒则重新计时return false;}return true;},child: Container(alignment: Alignment.center,child: Text("1秒内连续按两次返回键退出"),));}}
读者可以运行示例看看效果
