js实现数组去重的5种方法
for循环
for循环 + indexOf / includes
let arr = [1, 2, 1, 3, 2, 4, 3, 5, 4]let newArr = []for (let i = 0, l = arr.length; i < l; i++) {if (newArr.indexOf(arr[i]) === -1) {newArr.push(arr[i])}}console.log(newArr)
forEach + includes / indexOf
let arr = [1, 2, 1, 3, 2, 4, 3, 5, 4]let newArr = []arr.forEach(item => {if (!newArr.includes(item)) newArr.push(item)})console.log(newArr)
基于对象处理
let arr = [1, 2, 1, 3, 2, 4, 3, 5, 4]let obj = {}for (let i = 0; i < arr.length; i++) {let item = arr[i]// 如果对象中已经有该元素, 说明该元素是重复元素if (obj[item] !== undefined) {// 就把数组最后一位放在该位置, 相当于删掉了该元素arr[i] = arr[arr.length - 1]// 数组长度减1, 将最后一个元素去掉arr.length--// i减一, 保证下次循环从替换的元素开始i--continue}obj[item] = item}console.log(arr)
通过Set和拓展运算符…
let arr = [1, 2, 1, 3, 2, 4, 3, 5, 4]let newArr = [...new Set(arr)]console.log(newArr)
JS实现数组去重方法总结(六种方法)
1. 双层循环,外层循环元素,内层循环时比较值
如果有相同的值则跳过,不相同则push进数组:
Array.prototype.distinct = function(){var arr = this,result = [],i,j,len = arr.length;for(i = 0; i < len; i++){for(j = i + 1; j < len; j++){if(arr[i] === arr[j]){j = ++i;}}result.push(arr[i]);}return result;}var arra = [1,2,3,4,4,1,1,2,1,1,1];arra.distinct(); //返回[3,4,2,1]
2. 利用splice直接在原数组进行操作
双层循环,外层循环元素,内层循环时比较值
值相同时,则删去这个值
注意点:删除元素之后,需要将数组的长度也减1。
Array.prototype.distinct = function (){var arr = this,i,j,len = arr.length;for(i = 0; i < len; i++){for(j = i + 1; j < len; j++){if(arr[i] == arr[j]){arr.splice(j,1);len--;j--;}}}return arr;};var a = [1,2,3,4,5,6,5,3,2,4,56,4,1,2,1,1,1,1,1,1,];var b = a.distinct();console.log(b.toString()); //1,2,3,4,5,6,56
3. 利用对象的属性不能相同的特点进行去重
Array.prototype.distinct = function (){var arr = this,i,obj = {},result = [],len = arr.length;for(i = 0; i< arr.length; i++){if(!obj[arr[i]]){ //如果能查找到,证明数组元素重复了obj[arr[i]] = 1;result.push(arr[i]);}}return result;};var a = [1,2,3,4,5,6,5,3,2,4,56,4,1,2,1,1,1,1,1,1,];var b = a.distinct();console.log(b.toString()); //1,2,3,4,5,6,56
4. 数组递归去重
运用递归的思想
先排序,然后从最后开始比较,遇到相同,则删除:
Array.prototype.distinct = function (){var arr = this,len = arr.length;arr.sort(function(a,b){ //对数组进行排序才能方便比较return a - b;})function loop(index){if(index >= 1){if(arr[index] === arr[index-1]){arr.splice(index,1);}loop(index - 1); //递归loop函数进行去重}}loop(len-1);return arr;};var a = [1,2,3,4,5,6,5,3,2,4,56,4,1,2,1,1,1,1,1,1,56,45,56];var b = a.distinct();console.log(b.toString()); //1,2,3,4,5,6,45,56
5. 利用indexOf以及forEach
Array.prototype.distinct = function (){var arr = this,result = [],len = arr.length;arr.forEach(function(v, i ,arr){ //这里利用map,filter方法也可以实现var bool = arr.indexOf(v,i+1); //从传入参数的下一个索引值开始寻找是否存在重复if(bool === -1){result.push(v);}})return result;};var a = [1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,3,3,3,3,3,3,3,2,3,3,2,2,1,23,1,23,2,3,2,3,2,3];var b = a.distinct();console.log(b.toString()); //1,23,2,3
6. 利用ES6的Set
Set数据结构,它类似于数组,其成员的值都是唯一的。
*注意S大写
利用Array.from将Set结构转换成数组:
function dedupe(array){return Array.from(new Set(array));}dedupe([1,1,2,3]) //[1,2,3]
拓展运算符(…)内部使用for…of循环:
let arr = [1,2,3,3];let resultarr = [...new Set(arr)];console.log(resultarr); //[1,2,3]
