思路:回溯
cur_path 记录当前路径中的总和,如果在叶子节点上出现了cur_sum == target_sum,就将cur_path放到fit_path当中。否则就进行回溯操作。- 回溯的“回”如何实现?
cur_path.pop_back() 
代码:
/** * Definition for a binary tree node. * struct TreeNode { *     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode() : val(0), left(nullptr), right(nullptr) {} *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} * }; */class Solution {public:    vector<vector<int>> fit_path;    vector<int> cur_path;    void traceBack(TreeNode* root, int pre_sum, int targetSum) {        if (!root) {            return;        }        int cur_sum = pre_sum + root->val;        cur_path.push_back(root->val);        if (!root->left && !root->right) {            if (cur_sum == targetSum) {                fit_path.push_back(cur_path);            }        }        traceBack(root->left, cur_sum, targetSum);        traceBack(root->right, cur_sum, targetSum);        // 回溯的“回”操作        cur_path.pop_back();    }    vector<vector<int>> pathSum(TreeNode* root, int targetSum) {        traceBack(root, 0, targetSum);        return fit_path;    }};