下载下来图片，刚开始还好奇221B是什么16进制，点开图片就明白了。
    image.png
    stegsolve没发现什么异常。
    binwalk扫描出有一个zlib

    1. DECIMAL       HEXADECIMAL     DESCRIPTION
    2. --------------------------------------------------------------------------------
    3. 0             0x0             PNG image, 2856 x 4284, 8-bit/color RGB, non-interlaced
    4. 62            0x3E            Zlib compressed data, compressed
    5. 7693403       0x75645B        Zlib compressed data, default compression

    提取出来后是841个由0和1组成的字符串。
    很容易联想到可能是29*29的二维码。
    写出脚本：

    1. from PIL import Image
    3. qr_code = "1111111000100100110000111111110000010011011110010101000001101110100111010011010010111011011101000000111011110101110110111010010111101110001011101100000101110111000010010000011111111010101010101010111111100000000011100100110100000000100101101110000101010101000001101000011101011011011100101000001110010010001111011110010001100000101101100111111001010110101101110000100011110100110001001100010010101110000111111111110010100110101001111110010110001100110111110111000110011110010001111001110000100011010000110100100000001011001010101101110100011011010011100011101001111011111000101001101101101100101010001111101000000000011101101101010001011011111110000011110000101011010100000101011110010101000101101011101001010011001011111001010111010110101111000001101001101110100101010000010100111011000001000011101000011001001011111110100100100000111100110"
    5. im=Image.new("RGB",(29,29))
    6. count=0
    7. for i in range(29):
    8.     for j in range(29):
    9.         if qr_code[count] == '1':
    10.             im.putpixel((i,j),(0,0,0))
    11.         else:
    12.             im.putpixel((i,j),(255,255,255))
    13.         count+=1
    14. im.resize((im.width*2,im.height*2))
    15. im.save('exp.png')

    生成二维码，但是不知道为什么只有微信可以扫。