一、基本概念
1.1 基本定义
视图:MySQL从5.0.1版本开始提供视图功能。一种虚拟 存在的表,行和列的数据来自定义视图的查询中使用的表 ,并且是在使用视图时动态生成的,只保存了sql逻辑,不保存查询结果
比如:舞蹈班和普通班级的对比
创建语法的关键字 是否实际占用物理空间 使用
1.2 应用场景
- 多个地方用到同样的查询结果
- 该查询结果使用的sql语句较复杂
1.3 示例
#案例:查询姓张的学生名和专业名
SELECT stuname,majornameFROM stuinfo sINNER JOIN major m ON s.`majorid`= m.`id`WHERE s.`stuname` LIKE '张%';CREATE VIEW v1ASSELECT stuname,majornameFROM stuinfo sINNER JOIN major m ON s.`majorid`= m.`id`;SELECT * FROM v1 WHERE stuname LIKE '张%';
1.4 作用
- 重用sql语句
- 简化复杂的sql操作,不必知道它的查询细节
- 保护数据,提高安全性
1.5 视图和表的对比
| 视图 | create view | 只是保存了sql逻辑 | 增删改查,只是一般不能增删改 |
|---|---|---|---|
| 表 | create table | 保存了数据 | 增删改查 |
2.1 创建视图
语法:
create view 视图名
as
查询语句;
USE myemployees;
#1.查询姓名中包含a字符的员工名、部门名和工种信息
#①创建
CREATE VIEW myv1ASSELECT last_name,department_name,job_titleFROM employees eJOIN departments d ON e.department_id = d.department_idJOIN jobs j ON j.job_id = e.job_id;

#②使用
SELECT * FROM myv1 WHERE last_name LIKE '%a%';

#2.查询各部门的平均工资级别
#①创建视图查看每个部门的平均工资
CREATE VIEW myv2ASSELECT AVG(salary) ag,department_idFROM employeesGROUP BY department_id;
②使用
SELECT myv2.`ag`,g.grade_levelFROM myv2JOIN job_grades gON myv2.`ag` BETWEEN g.`lowest_sal` AND g.`highest_sal`;
#3.查询平均工资最低的部门信息
SELECT * FROM myv2 ORDER BY ag LIMIT 1;
#4.查询平均工资最低的部门名和工资
CREATE VIEW myv3ASSELECT * FROM myv2 ORDER BY ag LIMIT 1;SELECT d.*,m.agFROM myv3 mJOIN departments dON m.`department_id`=d.`department_id`;
2.2 视图的修改
方式一:
create or replace view 视图名
as
查询语句;
SELECT * FROM myv3CREATE OR REPLACE VIEW myv3ASSELECT AVG(salary),job_idFROM employeesGROUP BY job_id;
方式二:
语法:
alter view 视图名
as
查询语句;
ALTER VIEW myv3ASSELECT * FROM employees;
2.3 删除视图
语法:drop view 视图名,视图名,…;
DROP VIEW emp_v1,emp_v2,myv3;
SHOW CREATE VIEW myv3; —更具体的信息,包括创建后的大部分信息
<br /><a name="ViRxB"></a>### 2.5 视图的更新<br />先创建两个视图```sqlCREATE OR REPLACE VIEW myv1ASSELECT last_name,email,salary*12*(1+IFNULL(commission_pct,0)) "annual salary"FROM employees;CREATE OR REPLACE VIEW myv1ASSELECT last_name,emailFROM employees;
SELECT FROM myv1;
SELECT FROM employees;
2.5.1 插入
INSERT INTO myv1 VALUES('张飞','zf@qq.com');
- 会对原始表有修改!
- 所以往往会给视图设置权限
2.5.2 修改
UPDATE myv1 SET last_name = '张无忌' WHERE last_name='张飞';
2.5.3 删除
DELETE FROM myv1 WHERE last_name = '张无忌';
具备以下特点的视图不允许更新
#①包含以下关键字的sql语句:分组函数、distinct、group by、having、union或者union all
CREATE OR REPLACE VIEW myv1ASSELECT MAX(salary) m,department_idFROM employeesGROUP BY department_id;SELECT * FROM myv1;#更新UPDATE myv1 SET m=9000 WHERE department_id=10;

#②常量视图
CREATE OR REPLACE VIEW myv2ASSELECT 'john' NAME;SELECT * FROM myv2;#更新UPDATE myv2 SET NAME='lucy';
#③Select中包含子查询
CREATE OR REPLACE VIEW myv3ASSELECT department_id,(SELECT MAX(salary) FROM employees) 最高工资FROM departments;#更新SELECT * FROM myv3;UPDATE myv3 SET 最高工资=100000;
#④join
CREATE OR REPLACE VIEW myv4ASSELECT last_name,department_nameFROM employees eJOIN departments dON e.department_id = d.department_id;#更新SELECT * FROM myv4;UPDATE myv4 SET last_name = '张飞' WHERE last_name='Whalen';INSERT INTO myv4 VALUES('陈真','xxxx');

#⑤from一个不能更新的视图
CREATE OR REPLACE VIEW myv5ASSELECT * FROM myv3;#更新SELECT * FROM myv5;UPDATE myv5 SET 最高工资=10000 WHERE department_id=60;

#⑥where子句的子查询引用了from子句中的表
CREATE OR REPLACE VIEW myv6ASSELECT last_name,email,salaryFROM employeesWHERE employee_id IN(SELECT manager_idFROM employeesWHERE manager_id IS NOT NULL);#更新SELECT * FROM myv6;UPDATE myv6 SET salary=10000 WHERE last_name = 'k_ing';
三、案例 #一、创建视图emp_v1,要求查询电话号码以‘011’开头的员工姓名和工资、邮箱
CREATE OR REPLACE VIEW emp_v1ASSELECT last_name,salary,emailFROM employeesWHERE phone_number LIKE '011%';
#二、创建视图emp_v2,要求查询部门的最高工资高于12000的部门信息
CREATE OR REPLACE VIEW emp_v2ASSELECT MAX(salary) mx_dep,department_idFROM employeesGROUP BY department_idHAVING MAX(salary)>12000;SELECT d.*,m.mx_depFROM departments dJOIN emp_v2 mON m.department_id = d.`department_id`;

