源题目
https://leetcode-cn.com/problems/remove-nth-node-from-end-of-list/
19. 删除链表的倒数第 N 个结点
难度中等1514
给你一个链表,删除链表的倒数第 n 个结点,并且返回链表的头结点。
进阶:你能尝试使用一趟扫描实现吗?
示例 1:
输入:head = [1,2,3,4,5], n = 2 输出:[1,2,3,5]
示例 2:
输入:head = [1], n = 1 输出:[]
示例 3:
输入:head = [1,2], n = 1 输出:[1]
提示:
- 链表中结点的数目为 sz
- 1 <= sz <= 30
- 0 <= Node.val <= 100
- 1 <= n <= sz
/*** Definition for a singly-linked list.* class ListNode {* public $val = 0;* public $next = null;* function __construct($val = 0, $next = null) {* $this->val = $val;* $this->next = $next;* }* }*/class Solution {/*** @param ListNode $head* @param Integer $n* @return ListNode*/function removeNthFromEnd($head, $n) {if($head == null){return $head;}$newList = new ListNode();$newList->next = $head;$fast = $slow = $newList;for($i=0; $i<$n+1; $i++){$fast = $fast->next;}while($fast != null){$fast = $fast->next;$slow = $slow->next;}$slow->next = $slow->next->next;return $newList->next;}}
