A Simple String Class
#pragma once#include <iostream>#include <cstring>class MyString{private:int buf_len;char *characters;public:MyString(int buf_len = 64, const char *data = NULL){std::cout << "Constructor(int, char*)" << std::endl;this->buf_len = 0;this->characters = NULL;create(buf_len, data);}~MyString(){delete[] this->characters;}bool create(int buf_len, const char *data){this->buf_len = buf_len;if (this->buf_len != 0){this->characters = new char[this->buf_len]{};if (data)strncpy(this->characters, data, this->buf_len);}return true;}friend std::ostream &operator<<(std::ostream &os, const MyString &ms){os << "buf_len = " << ms.buf_len;os << ", characters = " << static_cast<void *>(ms.characters);os << " [" << ms.characters << "]";return os;}};
采用动态内存,再构造函数中申请内存,再析构函数中释放内存,是不是就万事大吉呢?我们运行一下程序
#include <iostream>#include "mystring.hpp"using namespace std;// Why memory leak and memory double free?int main(){MyString str1(10, "Shenzhen");cout << "str1: " << str1 << endl;MyString str2 = str1; // 调用了copy constructor,str1和str2 指向的相同的内存空间cout << "str2: " << str2 << endl;MyString str3; // 调用了默认的构造函数,cout << "str3: " << str3 << endl;str3 = str1; // 这时赋值操作,编译器会生成=的运算符重载,把str1的成员拷贝给str2cout << "str3:" << str3 << endl;return 0;}
这时这三个对象指向的内存空间相同,再程序即将完成退出之前,要执行析构函数对他们的内存销毁,执行完一个对象内存销毁之后,再进行第一个对象内存销毁时,就会出错。再str3创建的时候,会开辟一块内存空间,但是当str3 = str1之后,str3的变量characters修改了内存地址,所以没有变量指向这块内存地址,就会造成内存泄漏。
这种内存泄漏的bug非常难排查。那么应该如何避免呢?
