思路
顺序遍历
public int peakIndexInMountainArray(int[] A) {for(int i=1;i<A.length-1;i++){if(A[i]>A[i+1])return i;}return 0;}
二分查找
public int peakIndexInMountainArray(int[] A) {int low = 0;int high = A.length-1;while(low<=high){int mid = low + ((high-low)>>1);if(A[mid]>A[mid+1]&&A[mid]>A[mid-1]){return mid;}else if(A[mid]<A[mid+1]&&A[mid]>A[mid-1])low = mid+1;elsehigh = mid -1;}return -1;}
