小结:
- 如果没有出现异常,则执行try块中所有语句,不执行catch中所有的语句,如果有finaily,最后还需要执行finally里面的语句。
- 如果出现异常,则try块中异常发生后,try块剩下的语句不再执行。将执行catch块中的语句,如果有finally,最后还需要执行finally里面的语句! ```java package test;
public class Main { public static int method() { try { String[] names = new String[3];//String[]数组 if (names[1].equals(“tom”)) {//NullPointerException System.out.println(names[1]); } else { names[3] = “WTY2002”; } return 1; } catch (ArrayIndexOutOfBoundsException e) { return 2; } catch (NullPointerException e) {//捕获 return 3; } finally { //必须执行 return 4; //返回4 } }
public static void main(String[] args) {System.out.println(method()); //4}
}
```javapackage test;public class Main {}class Exception {public static int method() {int i = 1;try {i++; //i = 2String[] names = new String[3];if (names[1].equals("tom")) {//空指针System.out.println(names[1]);} else {names[3] = "WTY2002";}return 1;} catch (ArrayIndexOutOfBoundsException e) {return 2;} catch (NullPointerException e) {System.out.println("========");return ++i; //i = 3} finally {//必须执行return ++i; //i = 4}}public static void main(String[] args) {System.out.println(method());}}

package test;public class Main {}class ExceptionExe01 {public static int method() {int i = 1;//i = 1try {i++;// i=2String[] names = new String[3];if (names[1].equals("tom")) { //空指针System.out.println(names[1]);} else {names[3] = "hspedu";}return 1;} catch (ArrayIndexOutOfBoundsException e) {return 2;} catch (NullPointerException e) {return ++i; // i = 3 => 保存临时变量 temp = 3;} finally {++i; //i = 4System.out.println("i=" + i);// i = 4}}public static void main(String[] args) {System.out.println(method());// 3}}

package test;import java.util.Scanner;public class Main {public static void main(String[] args) {//如果用户输入的不是一个整数,就提示他反复输入,直到输入一个整数为止//思路//1. 创建Scanner对象//2. 使用无限循环,去接收一个输入//3. 然后将该输入的值,转成一个int//4. 如果在转换时,抛出异常,说明输入的内容不是一个可以转成int的内容//5. 如果没有抛出异常,则break 该循环Scanner scanner = new Scanner(System.in);int num = 0;String inputStr = "";while (true) {System.out.println("请输入一个整数:"); //inputStr = scanner.next();try {num = Integer.parseInt(inputStr); //这里是可能抛出异常break;} catch (NumberFormatException e) {System.out.println("你输入的不是一个整数:");}}System.out.println("你输入的值是 = " + num);}}

