题目链接:https://leetcode-cn.com/problems/fan-zhuan-lian-biao-lcof/
难度:简单
描述:
定义一个函数,输入一个链表的头节点,反转该链表并输出反转后链表的头节点。
题解
# Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = Noneclass Solution:def reverseList(self, head: ListNode) -> ListNode:pre = Nonecur = headwhile cur is not None:temp = curcur = cur.nexttemp.next = prepre = tempreturn pre
