题目链接:https://leetcode-cn.com/problems/binary-tree-preorder-traversal/
难度:简单
描述:
给你二叉树的根节点 root
,返回它节点值的 前序 遍历。
提示:
节点数:[0, 100]
题解
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def preorderTraversal(self, root: Optional[TreeNode]) -> List[int]:
ret = []
def recursion(root):
if root is None:
return
ret.append(root.val)
recursion(root.left)
recursion(root.right)
recursion(root)
return ret
class Solution:
def preorderTraversal(self, root: Optional[TreeNode]) -> List[int]:
if root is None:
return []
ret = []
stk = [root]
while stk != []:
temp_node = stk.pop()
ret.append(temp_node.val)
if temp_node.right is not None:
stk.append(temp_node.right)
if temp_node.left is not None:
stk.append(temp_node.left)
return ret