题目链接:https://leetcode-cn.com/problems/er-cha-shu-de-jing-xiang-lcof/
难度:简单
描述:
请完成一个函数,输入一个二叉树,该函数输出它的镜像。
题解
# Definition for a binary tree node.# class TreeNode:# def __init__(self, x):# self.val = x# self.left = None# self.right = Noneclass Solution:def mirrorTree(self, root: TreeNode) -> TreeNode:def recursion(root):if root is None:returnroot.left, root.right = root.right, root.leftrecursion(root.left)recursion(root.right)recursion(root)return root
