Python 入门练习 - 图1
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Notation: Those Challenges come from Rosalind

Introduction

Function:

  1. def run(a, b):
  2.   Result = a + b
  3.   print("hello function")
  4.   return Result

Function test:

  1. C = run(1 , 5)
  2. print(C)
  1. hello function
  2. 6

Let the fun begin!

Calculate

Link
Given: Two positive integers a and b, each less than 1000.
Return: The integer corresponding to the square of the hypotenuse of the right triangle whose legs have lengths a and b.

  1. in: 3 5
  2. out: 34
  1. def run(a, b):
  2.   Result = (a+b)**2 - 2ab
  3.   print(Result)
  5. run(3, 4)

String splice

Link
Given: A string s of length at most 200 letters and four integers a, b, c and d.
Return: The slice of this string from indices a through b and c through d (with space in between), inclusively. In other words, we should include elements s[b] and s[d] in our slice.

  1. in:
  2. HumptyDumptysatonawallHumptyDumptyhadagreatfallAlltheKingshorsesandalltheKingsmenCouldntputHumptyDumptyinhisplaceagain.
  3. 22 27 97 102
  5. out:
  6. Humpty Dumpty
  1. def run(Str, a, b, c, d):
  2.   Result = Str[a:b+1] + " " Str[c:d+1]
  3.   print(Result)
  5. Str = "HumptyDumptysatonawallHumptyDumptyhadagreatfallAlltheKingshorsesandalltheKingsmenCouldntputHumptyDumptyinhisplaceagain."
  6. a = 22; b = 27; c = 97; d = 102
  8. run(Str, a, b, c, d)

loop

Link
Given: Two positive integers a and b (a Return: The sum of all odd integers from a through b, inclusively.

  1. in:
  2. 100 200
  3. out:
  4. 7500
  1. def run(a, b):
  2.   List = [a, b]
  3.   List.sort()
  4.   Result = 0
  5.   for i in range(List[0], List[1]+1):
  6.     if i % 2 == 1:
  7.       Result += i
  8.   print(Result)
  10. run(100, 200)

Reading and writing

Link
Given: A file containing at most 1000 lines.
Return: A file containing all the even-numbered lines from the original file. Assume 1-based numbering of lines.

  1. def run(INPUT, OUTPUT):
  2.   In = open(INPUT, 'r').readlines()
  3.   Num = 0
  4.   Result = ""
  5.   for i in In:
  6.     if Num % 2 == 1:
  7.       Result += i
  8.     Num += 1
  9.   print(Result)
  10.   F = open(OUTPUT, 'w')
  11.   F.write(Result)
  12.   F.close()

Words count

Link
Given: A string s of length at most 10000 letters.
Return: The number of occurrences of each word in s, where words are separated by spaces. Words are case-sensitive, and the lines in the output can be in any order.

  1. In:
  2. We tried list and we tried dicts also we tried Zen
  4. Out:
  5. and 1
  6. We 1
  7. tried 3
  8. dicts 1
  9. list 1
  10. we 2
  11. also 1
  12. Zen 1
  1. def run(Str):
  2.   List = Str.split(" ")
  3.   Index = list(set(List))
  4.   Result = ""
  5.   for i in Index:
  6.     if i != "":
  7.       Result += i +" " + str(List.count(i)) +"\n"
  8.   print(Result)

Enjoy~

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