前面就是binwalk+ARCHPR,然后会出来下面这个flag文件,长度很长。。。
这里用字符统计脚本,然后按字符从多到少,排序输出即可
# -*- coding:utf-8 -*-#Author: mochu7alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890!@#$%^&*()_+- =\\{\\}[]"strings = open('./flag.txt').read()result = {}for i in alphabet:counts = strings.count(i)i = '{0}'.format(i)result[i] = countsres = sorted(result.items(),key=lambda item:item[1],reverse=True)for data in res:print(data)for i in res:flag = str(i[0])print(flag[0],end="")

