前面就是binwalk+ARCHPR,然后会出来下面这个flag文件,长度很长。。。
这里用字符统计脚本,然后按字符从多到少,排序输出即可
# -*- coding:utf-8 -*-
#Author: mochu7
alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890!@#$%^&*()_+- =\\{\\}[]"
strings = open('./flag.txt').read()
result = {}
for i in alphabet:
counts = strings.count(i)
i = '{0}'.format(i)
result[i] = counts
res = sorted(result.items(),key=lambda item:item[1],reverse=True)
for data in res:
print(data)
for i in res:
flag = str(i[0])
print(flag[0],end="")