public void merge(int[] nums1, int m, int[] nums2, int n) {
// two get pointers for nums1 and nums2
int p1 = m - 1;
int p2 = n - 1;
// set pointer for nums1
int p = m + n - 1;
// while there are still elements to compare
while ((p1 >= 0) && (p2 >= 0))
// compare two elements from nums1 and nums2
// and add the largest one in nums1
nums1[p--] = (nums1[p1] < nums2[p2]) ? nums2[p2--] : nums1[p1--];
// add missing elements from nums2
System.arraycopy(nums2, 0, nums1, 0, p2 + 1);///上面减1了,移动元素的个数。
// 作者:LeetCode
// 链接:https://leetcode-cn.com/problems/merge-sorted-array/solution/he-bing-liang-ge-you-xu-shu-zu-by-leetcode/
}
System.arraycopy(nums2, 0, nums1, m, n);//移动元素的个数
Arrays.sort(nums1);