14-December-2021 Homework

    Find the integrals. (You can use any method you learned from the course. Not all problems require integration by parts.)

    Solutions.

    1. sol141221 - 图1%2BC#card=math&code=%5Cint%20x%5E3%20%5Cln%20x%20%5C%2C%20dx%20%3D%20%5Cfrac%7Bx%5E4%7D%7B16%7D%284%5Cln%20x%20-1%29%2BC&id=zubU7)
    2. sol141221 - 图2%20%5C%2C%20dx%20%3D%20%5Cfrac%7B2x%2B1%7D%7B2%7D(%5Cln%20%7C2x%2B1%7C%20-1)%2BC#card=math&code=%5Cint%20%5Cln%282x%2B1%29%20%5C%2C%20dx%20%3D%20%5Cfrac%7B2x%2B1%7D%7B2%7D%28%5Cln%20%7C2x%2B1%7C%20-1%29%2BC&id=pe4YB)
    3. sol141221 - 图3%20%5C%2C%20dx%20%3D%20%5Cint%20%5Ctan%5E%7B-1%7D(x)%5C%2C%20dx%20%3D%20x%5Carctan%20x%20-%20(1%2F2)%5Cln(1%2Bx%5E2)%2BC#card=math&code=%5Cint%20%5Carctan%28x%29%20%5C%2C%20dx%20%3D%20%5Cint%20%5Ctan%5E%7B-1%7D%28x%29%5C%2C%20dx%20%3D%20x%5Carctan%20x%20-%20%281%2F2%29%5Cln%281%2Bx%5E2%29%2BC&id=MqUSp)
    4. sol141221 - 图4%5C%2C%20dx%20%3D%20(1%2F4)(%5Csin%20(2x)%20-%202x%20%5Ccos(2x))%2BC#card=math&code=%5Cint%20x%20%5Csin%282x%29%5C%2C%20dx%20%3D%20%281%2F4%29%28%5Csin%20%282x%29%20-%202x%20%5Ccos%282x%29%29%2BC&id=jyebo)
    5. sol141221 - 图5
    6. sol141221 - 图6(4x%5E3-6x%5E2%2B6x-3)%2BC#card=math&code=%5Cint%20x%5E3%20%5Cmathrm%7Be%7D%5E%7B2x%7D%5C%2C%20dx%20%3D%20%28e%5E%7B2x%7D%2F8%29%284x%5E3-6x%5E2%2B6x-3%29%2BC&id=VBce3)
    7. sol141221 - 图7e%5E%7B-x%5E2%7D%2BC#card=math&code=%5Cint%20x%20%5Cmathrm%7Be%7D%5E%7B-x%5E2%7D%5C%2C%20dx%20%3D%20%28-1%2F2%29e%5E%7B-x%5E2%7D%2BC&id=rwiWY)
    8. sol141221 - 图8%20%5C%2C%20dx%2C%20%5Cquad%20I_2%20%3D%20%5Cint%20%5Ccos(%5Cln%20x)%5C%2C%20dx#card=math&code=I_1%20%3D%20%5Cint%20%5Csin%20%28%5Cln%20x%29%20%5C%2C%20dx%2C%20%5Cquad%20I_2%20%3D%20%5Cint%20%5Ccos%28%5Cln%20x%29%5C%2C%20dx&id=CGMl1) (Hint: let sol141221 - 图9, or you can use integration by parts and simultaneously solve out these two integrals)
      Solution: sol141221 - 图10%5Cleft(%5Csin%20(%5Cln%20x)-%5Ccos%20(%5Cln%20x)%5Cright)%2C%5Cquad%20%20I_2%20%3D(x%2F2)%20%5Cleft(%5Csin(%5Cln%20x)%2B%5Ccos(%5Cln%20(x))%20%5Cright)#card=math&code=I_1%20%3D%20%28x%2F2%29%5Cleft%28%5Csin%20%28%5Cln%20x%29-%5Ccos%20%28%5Cln%20x%29%5Cright%29%2C%5Cquad%20%20I_2%20%3D%28x%2F2%29%20%5Cleft%28%5Csin%28%5Cln%20x%29%2B%5Ccos%28%5Cln%20%28x%29%29%20%5Cright%29&id=kSO7Z).
    9. sol141221 - 图11%5E2%5C%2C%20dx%20%3D%20x(%5Cln%5E2(x)-2%5Cln%20(x)%2B2)%2BC#card=math&code=%5Cint%20%28%5Cln%20x%29%5E2%5C%2C%20dx%20%3D%20x%28%5Cln%5E2%28x%29-2%5Cln%20%28x%29%2B2%29%2BC&id=vpdfC)
    10. sol141221 - 图12%20%5C%2C%20dx%20%3D%20%5Cint%20%5Csin%5E%7B-1%7D%20x%20%5C%2C%20dx%20%3D%20x%5Carcsin(x)%2B%5Csqrt%7B1-x%5E2%7D%2BC#card=math&code=%5Cint%20%5Carcsin%28x%29%20%5C%2C%20dx%20%3D%20%5Cint%20%5Csin%5E%7B-1%7D%20x%20%5C%2C%20dx%20%3D%20x%5Carcsin%28x%29%2B%5Csqrt%7B1-x%5E2%7D%2BC&id=wUbCx)
    11. sol141221 - 图13%5C%2C%20dx%20%3D%20%5Cint%20x%20%5Ctan%5E%7B-1%7D%20(x)%20%5C%2C%20dx%20%3D%20(1%2F2)%5Cleft(%20x%20%5Carctan(x)%20-x%20%2B%20%5Carctan(x)%5Cright)%20%2BC#card=math&code=%5Cint%20x%20%5Carctan%28x%29%5C%2C%20dx%20%3D%20%5Cint%20x%20%5Ctan%5E%7B-1%7D%20%28x%29%20%5C%2C%20dx%20%3D%20%281%2F2%29%5Cleft%28%20x%20%5Carctan%28x%29%20-x%20%2B%20%5Carctan%28x%29%5Cright%29%20%2BC&id=YGt58)
    12. sol141221 - 图14%5E%7B5%2F2%7D%7D%7B5%7D%2B(2x-3)%5E%7B3%2F2%7D%2BC#card=math&code=%5Cint%202x%5Csqrt%7B2x-3%7D%5C%2C%20dx%20%3D%20%5Cfrac%7B%282x-3%29%5E%7B5%2F2%7D%7D%7B5%7D%2B%282x-3%29%5E%7B3%2F2%7D%2BC&id=MriJm)

    Derive the following formulas using the technique of integration by parts. Assume that sol141221 - 图15 is a positive integer. These formulas are called reduction formulas because the exponent in the sol141221 - 图16 term has been reduced by one in each case. The second integral is simpler than the original integral.

    1. sol141221 - 图17.
      Solution: sol141221 - 图18#card=math&code=In%20%3D%20x%5En%20e%5Ex%20-%20n%20I%7Bn-1%7D%5C%2C%20%28n%20%5Cgeq%201%29&id=hQxIJ). (Note that sol141221 - 图19e%5Ex%2BC%2C%20%20%5Cquad%20I_0%20%3D%20%5Cint%20e%5Ex%20%5C%2C%20dx%20%3D%20e%5Ex%20%2BC#card=math&code=I_1%20%3D%20%5Cint%20xe%5Ex%20%5C%2C%20dx%20%3D%28x-1%29e%5Ex%2BC%2C%20%20%5Cquad%20I_0%20%3D%20%5Cint%20e%5Ex%20%5C%2C%20dx%20%3D%20e%5Ex%20%2BC&id=Q6zsp).)
    2. sol141221 - 图20%5C%2C%20dx#card=math&code=In%3D%5Cint%20x%5En%20%5Ccos%20%28x%29%5C%2C%20dx&id=eo6Bu)
      Solution: sol141221 - 图21I
      %7Bn-2%7D#card=math&code=In%20%20%3D%20x%5En%20%5Csin%20x%20%2B%20nx%5E%7Bn-1%7D%5Ccos%20x%20-%20n%28n-1%29I%7Bn-2%7D&id=WoDJk). Here we have to apply the integration by parts twice to get the reduction formula.
      (Note that sol141221 - 图22%5C%2C%20dx%20%3D%20%5Csin%20(x)%2BC%2C%20%5Cquad%20I_1%20%3D%20%5Cint%20x%5Ccos(x)%5C%2C%20dx%3D%20x%5Csin(x)%2B%5Ccos(x)%2BC#card=math&code=I_0%20%3D%20%5Cint%20%5Ccos%20%28x%29%5C%2C%20dx%20%3D%20%5Csin%20%28x%29%2BC%2C%20%5Cquad%20I_1%20%3D%20%5Cint%20x%5Ccos%28x%29%5C%2C%20dx%3D%20x%5Csin%28x%29%2B%5Ccos%28x%29%2BC&id=IL7mx).)
    3. sol141221 - 图23%5C%2C%20dx#card=math&code=I_n%20%3D%20%5Cint%20%5Ctan%5En%28x%29%5C%2C%20dx&id=dsBpK) (Hint: sol141221 - 图24, and hence sol141221 - 图25%20)-%20dx#card=math&code=%5Ctan%5E2%20x%5C%2C%20dx%20%3D%20d%28%5Ctan%28x%29%20%29-%20dx&id=pER08).)
      Solution: For sol141221 - 图26, using the hint, we have

      1. ![](https://g.yuque.com/gr/latex?%5Cbegin%7Baligned%7D%0AI_n%20%26%3D%20%5Cint%20%5Ctan%5E%7Bn-2%7D(x)%5C%2C%20d(%5Ctan(x))%20-%20I_%7Bn-2%7D%20%5C%5C%0A%26%3D-I_%7Bn-2%7D%2B%5Ctan%5E%7Bn-1%7D(x)%20-%20%5Cint%20%5Ctan(x)%20(n-2)%20%5Ctan%5E%7Bn-3%7D(x)%20d(%5Ctan(x))%5C%5C%0A%26%3D-I_%7Bn-2%7D%2B%5Ctan%5E%7Bn-1%7D(x)-(n-2)%5Cint%20%5Ctan%5E%7Bn-2%7D(x)%5C%2C%20d(%5Ctan(x))%5C%5C%0A%26%3D%20-I_%7Bn-2%7D%2B%5Ctan%5E%7Bn-1%7D(x)-%5Cfrac%7Bn-2%7D%7Bn-1%7D%5Ctan%5E%7Bn-1%7D(x)%5C%5C%0A%26%3D-I_%7Bn-2%7D%2B%5Cfrac%7B1%7D%7Bn-1%7D%5Ctan%5E%7Bn-1%7D(x).%20%0A%5Cend%7Baligned%7D%0A#card=math&code=%5Cbegin%7Baligned%7D%0AI_n%20%26%3D%20%5Cint%20%5Ctan%5E%7Bn-2%7D%28x%29%5C%2C%20d%28%5Ctan%28x%29%29%20-%20I_%7Bn-2%7D%20%5C%5C%0A%26%3D-I_%7Bn-2%7D%2B%5Ctan%5E%7Bn-1%7D%28x%29%20-%20%5Cint%20%5Ctan%28x%29%20%28n-2%29%20%5Ctan%5E%7Bn-3%7D%28x%29%20d%28%5Ctan%28x%29%29%5C%5C%0A%26%3D-I_%7Bn-2%7D%2B%5Ctan%5E%7Bn-1%7D%28x%29-%28n-2%29%5Cint%20%5Ctan%5E%7Bn-2%7D%28x%29%5C%2C%20d%28%5Ctan%28x%29%29%5C%5C%0A%26%3D%20-I_%7Bn-2%7D%2B%5Ctan%5E%7Bn-1%7D%28x%29-%5Cfrac%7Bn-2%7D%7Bn-1%7D%5Ctan%5E%7Bn-1%7D%28x%29%5C%5C%0A%26%3D-I_%7Bn-2%7D%2B%5Cfrac%7B1%7D%7Bn-1%7D%5Ctan%5E%7Bn-1%7D%28x%29.%20%0A%5Cend%7Baligned%7D%0A&id=mQuJ2)<br /> Note that ![](https://g.yuque.com/gr/latex?I_0%20%3D%20x%2BC%2C%20I_1%20%3D%20%5Cint%20%5Ctan%20(x)%20%5C%2C%20dx%20%3D%20-%5Cln(%5Ccos(x))%2BC#card=math&code=I_0%20%3D%20x%2BC%2C%20I_1%20%3D%20%5Cint%20%5Ctan%20%28x%29%20%5C%2C%20dx%20%3D%20-%5Cln%28%5Ccos%28x%29%29%2BC&id=AWjZh).