Ideas to find anti-derivatives

    1. Know the table of basic integrals.

    2. identify the given function, is it algebraic (monomial/power functions)? trigonometric? expoential? logarithmic? or anti-trigonometric?

    3. Or the sum of these five types? Then separate the summands.(see thm. 4.16)

    4. Or is it a product of these five types? Then integral by parts (—> the derivative formula for products)

    5. Try substitution, to reduce to the above cases.

    6. The case of rational functions (reduction to partial fractions)

    Glossary Remark: anti-derivative = indefinite integral


    Example 4.50

    a. Which 02-NOV - 图1) will have derivative 02-NOV - 图2%3D3x%5E2#card=math&code=F%27%28x%29%3D3x%5E2)? 02-NOV - 图3%20%3D%20x%5En%20%5CRightarrow%20F’(x)%3Dn%20x%5E%7Bn-1%7D#card=math&code=F%28x%29%20%3D%20x%5En%20%5CRightarrow%20F%27%28x%29%3Dn%20x%5E%7Bn-1%7D). Comparing the exponent, we have 02-NOV - 图4. So 02-NOV - 图5. So that 02-NOV - 图6%3Dx%5E3#card=math&code=F%28x%29%3Dx%5E3) gives 02-NOV - 图7%3D3x%5E2#card=math&code=F%27%28x%29%3D3x%5E2). Thus, all anti-derivatives for 02-NOV - 图8 are 02-NOV - 图9

    b. 02-NOV - 图10. So all anti-derivatives are 02-NOV - 图11%2BC#card=math&code=%5Cln%28x%29%2BC)

    c. 02-NOV - 图12‘%3D%5Ccos(x)#card=math&code=%5Csin%28x%29%27%3D%5Ccos%28x%29) So all anti-derivatives are 02-NOV - 图13%2BC#card=math&code=%5Csin%28x%29%2BC)

    d. 02-NOV - 图14‘%20%3D%20e%5Ex#card=math&code=%28e%5Ex%29%27%20%3D%20e%5Ex). So all anti-derivatives are 02-NOV - 图15.


    Comparison of derivatives and anti-derivatives:

    1. About summation. 02-NOV - 图16‘%3D%20f’%2Bg’#card=math&code=%28f%2Bg%29%27%3D%20f%27%2Bg%27), 02-NOV - 图17%2Bg(x))%20dx%20%3D%20%5Cint%20f(x)dx%20%2B%20%5Cint%20g(x)%20dx#card=math&code=%5Cint%20%28f%28x%29%2Bg%28x%29%29%20dx%20%3D%20%5Cint%20f%28x%29dx%20%2B%20%5Cint%20g%28x%29%20dx)

    2. about constant multiple: 02-NOV - 图18)’%20%3D%20C%20f’(x)#card=math&code=%28Cf%28x%29%29%27%20%3D%20C%20f%27%28x%29) , 02-NOV - 图19)%20dx%20%3D%20C%20%5Cint%20f(x)%20dx#card=math&code=%5Cint%20%28C%20f%28x%29%29%20dx%20%3D%20C%20%5Cint%20f%28x%29%20dx) .
      The above two properties are summarized in thm 4.16.

    3. about scalar 02-NOV - 图20, the power rule for integrals (thm 4.15 in the textbook) only requires that 02-NOV - 图21.
      Now we take 02-NOV - 图22 in thm 4.15, we get 02-NOV - 图23 (because 02-NOV - 图24)


    The indefinite integral for exponential functions

    $\int a^x dx = \frac{a^x}{\ln a} +C $ <—> 02-NOV - 图25‘%3Da%5Ex%20%5Cln%20a#card=math&code=%28a%5Ex%29%27%3Da%5Ex%20%5Cln%20a)

    Verification: 02-NOV - 图26‘%20%3D%20%5Cfrac%7B1%7D%7B%5Cln%20a%7D%20(a%5Ex)’%20%3D%20%5Cfrac%7B1%7D%7B%5Cln%20a%7D%20a%5Ex%20%5Cln%20a%20%3Da%5Ex#card=math&code=%28a%5Ex%2F%5Cln%20a%29%27%20%3D%20%5Cfrac%7B1%7D%7B%5Cln%20a%7D%20%28a%5Ex%29%27%20%3D%20%5Cfrac%7B1%7D%7B%5Cln%20a%7D%20a%5Ex%20%5Cln%20a%20%3Da%5Ex)

    Now if 02-NOV - 图27, then 02-NOV - 图28. So 02-NOV - 图29


    02-NOV - 图30%2Bg(x))%20dx%20%3D%20%5Cint%20f(x)%20dx%20%2B%20%5Cint%20g(x)dx%20%20%3DF(x)%20%2BC_1%20%2BG(x)%20%2BC_2%20%3DF(x)%2BG(x)%20%2BC#card=math&code=%5Cint%20%28f%28x%29%2Bg%28x%29%29%20dx%20%3D%20%5Cint%20f%28x%29%20dx%20%2B%20%5Cint%20g%28x%29dx%20%20%3DF%28x%29%20%2BC_1%20%2BG%28x%29%20%2BC_2%20%3DF%28x%29%2BG%28x%29%20%2BC)

    Only one constant at the last step is enough.


    Example 4.52

    $x^{1/3}/x = x{-2/3} $ Now use the power rule 02-NOV - 图31%20%2BC#card=math&code=%5Cint%20x%5En%20dx%20%3D%20x%5E%7Bn%2B1%7D%2F%28n%2B1%29%20%2BC)

    02-NOV - 图32%5Ccos(x)%20%3D%20%5Csin(x)#card=math&code=%5Ctan%28x%29%5Ccos%28x%29%20%3D%20%5Csin%28x%29), 02-NOV - 图33%20dx%20%3D%20-%5Ccos(x)%2BC#card=math&code=%5Cint%20%5Csin%28x%29%20dx%20%3D%20-%5Ccos%28x%29%2BC)


    Prob. 472. 02-NOV - 图34%20x%5E2%20-%20x%5E3%2F3%20%2BC#card=math&code=%5Cint%20e%5Ex%20%2B%203x%20-x%5E2%20dx%20%3D%20%5Cint%20e%5Ex%20dx%20%2B%203%20%5Cint%20x%20dx%20-%20%5Cint%20x%5E2%20dx%20%3D%20%20%20%20e%5Ex%20%20%2B%20%283%2F2%29%20x%5E2%20-%20x%5E3%2F3%20%2BC)

    Prob. 498 To find out 02-NOV - 图35 , we shall ask which function 02-NOV - 图36#card=math&code=F%28x%29) will have 02-NOV - 图37%3De%5E%7B-x%7D#card=math&code=F%27%28x%29%3De%5E%7B-x%7D) .

    02-NOV - 图38‘%20%3D%20-%20e%5E%7B-x%7D#card=math&code=%28e%5E%7B-x%7D%29%27%20%3D%20-%20e%5E%7B-x%7D) . So 02-NOV - 图39%20%3D%20-e%5E%7B-x%7D#card=math&code=F%28x%29%20%3D%20-e%5E%7B-x%7D) This implies that 02-NOV - 图40