- 例子1:客户端发送信息给服务端,服务端将数据显示在控制台上
```java package com.atguigu.java2;
import org.junit.Test;
import java.io.ByteArrayOutputStream; import java.io.IOException; import java.io.InputStream; import java.io.OutputStream; import java.net.InetAddress; import java.net.ServerSocket; import java.net.Socket;
/**
- 实现TCP的网络编程
- 例子1:客户端发送信息给服务端,服务端将数据显示在控制台上 *
- @author Dxkstart
@create 2021-06-04 18:07 */ public class TCPTest {
@Test public void client() {//客户端
Socket socket = null;
OutputStream os = null;
try {
//1.创建Socket对象,指明服务器端的ip和端口号
InetAddress inet = InetAddress.getByName("127.0.0.1");
socket = new Socket(inet,8899);
//2.获取一个输出流,用于输出数据
os = socket.getOutputStream();
//3.写出数据的操作
os.write("你好我是客户端MM".getBytes());
} catch (IOException e) {
e.printStackTrace();
} finally {
//4.资源的关闭
try {
if(os != null) {
os.close();
}
} catch (IOException e) {
e.printStackTrace();
}
try {
if(socket != null) {
socket.close();
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
@Test
public void server(){//服务端
ServerSocket ss = null;
InputStream is = null;
Socket socket = null;
ByteArrayOutputStream baos = null;
try {
//1.创建服务器短的ServerSocket,指明自己的端口号
ss = new ServerSocket(8899);
//2.调用accept()表示接收来自于客户端的socket
socket = ss.accept();
//3.获取输入流
is = socket.getInputStream();
//不建议这么写,可能会出现乱码,一个汉字占3个字节
// byte[] buffer = new byte[200]; // int len; // while((len = is.read(buffer)) != -1 ){ // String str = new String(buffer, 0, len); // System.out.print(str); // }
//4.读取输入流中的数据
baos = new ByteArrayOutputStream();
byte[] buffer = new byte[5];
int len;
while ((len = is.read(buffer)) != -1){
baos.write(buffer,0,len);
}
System.out.println(baos.toString());
} catch (IOException e) {
e.printStackTrace();
} finally {
//5.资源的关闭
try {
if(baos != null) {
baos.close();
}
} catch (IOException e) {
e.printStackTrace();
}
try {
if(is != null) {
is.close();
}
} catch (IOException e) {
e.printStackTrace();
}
try {
if(ss != null) {
ss.close();
}
} catch (IOException e) {
e.printStackTrace();
}
try {
if(socket != null) {
socket.close();
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
```