
思路:
- 利用数字转字符,chr(num)
- 上述变换,抽象为数学形式就是 abs(i-j) + ascall_A,然后再转换成对应的ascall码
# ABCDEFG# BABCDEF# CBABCDE# DCBABCD# EDCBABC# A -> 65n, m = input().split()n, m = int(n), int(m) # n行,m列ascall_A = 65# print(row)for i in range(n):for j in range(m):char_num = abs(i-j) + ascall_Aprint(chr(char_num), end='')print('')
