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    思路

    • 利用数字转字符,chr(num)
    • 上述变换,抽象为数学形式就是 abs(i-j) + ascall_A,然后再转换成对应的ascall码
    1. # ABCDEFG
    2. # BABCDEF
    3. # CBABCDE
    4. # DCBABCD
    5. # EDCBABC
    6. # A -> 65
    7. n, m = input().split()
    8. n, m = int(n), int(m) # n行,m列
    9. ascall_A = 65
    10. # print(row)
    11. for i in range(n):
    12. for j in range(m):
    13. char_num = abs(i-j) + ascall_A
    14. print(chr(char_num), end='')
    15. print('')