思路:
- 利用数字转字符,chr(num)
- 上述变换,抽象为数学形式就是 abs(i-j) + ascall_A,然后再转换成对应的ascall码
# ABCDEFG
# BABCDEF
# CBABCDE
# DCBABCD
# EDCBABC
# A -> 65
n, m = input().split()
n, m = int(n), int(m) # n行,m列
ascall_A = 65
# print(row)
for i in range(n):
for j in range(m):
char_num = abs(i-j) + ascall_A
print(chr(char_num), end='')
print('')