https://leetcode-cn.com/problems/convert-sorted-array-to-binary-search-tree/
题目
思路
代码
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def sortedArrayToBST(self, nums: List[int]) -> TreeNode:
def helper(left, right):
if left > right:
return None
# 总是选择中间位置左边的数字作为根节点
mid = (left + right) // 2
root = TreeNode(nums[mid])
root.left = helper(left, mid - 1)
root.right = helper(mid + 1, right)
return root
return helper(0, len(nums) - 1)