/** * Menu * @author lcry */@Data@Builderpublic class Menu {    /**     * id     */    public Integer id;    /**     * 名称     */    public String name;    /**     * 父id ,根节点为0     */    public Integer parentId;    /**     * 子节点信息     */    public List<Menu> childList;    public Menu(Integer id, String name, Integer parentId) {        this.id = id;        this.name = name;        this.parentId = parentId;    }    public Menu(Integer id, String name, Integer parentId, List<Menu> childList) {        this.id = id;        this.name = name;        this.parentId = parentId;        this.childList = childList;    }}
 @Test    public void testtree(){        //模拟从数据库查询出来        List<Menu> menus = Arrays.asList(                new Menu(1,"根节点",0),                new Menu(2,"子节点1",1),                new Menu(3,"子节点1.1",2),                new Menu(4,"子节点1.2",2),                new Menu(5,"根节点1.3",2),                new Menu(6,"根节点2",1),                new Menu(7,"根节点2.1",6),                new Menu(8,"根节点2.2",6),                new Menu(9,"根节点2.2.1",7),                new Menu(10,"根节点2.2.2",7),                new Menu(11,"根节点3",1),                new Menu(12,"根节点3.1",11)        );        //获取父节点        List<Menu> collect = menus.stream().filter(m -> m.getParentId() == 0).map(                (m) -> {                    m.setChildList(getChildrens(m, menus));                    return m;                }        ).collect(Collectors.toList());        System.out.println("-------转json输出结果-------");        System.out.println(JSON.toJSON(collect));    }    /**     * 递归查询子节点     * @param root  根节点     * @param all   所有节点     * @return 根节点信息     */    private List<Menu> getChildrens(Menu root, List<Menu> all) {        List<Menu> children = all.stream().filter(m -> {            return Objects.equals(m.getParentId(), root.getId());        }).map(                (m) -> {                    m.setChildList(getChildrens(m, all));                    return m;                }        ).collect(Collectors.toList());        return children;    }