Transposed Convolution

:label:sec_transposed_conv

The CNN layers we have seen so far, such as convolutional layers (:numref:sec_conv_layer) and pooling layers (:numref:sec_pooling), typically reduce (downsample) the spatial dimensions (height and width) of the input, or keep them unchanged. In semantic segmentation that classifies at pixel-level, it will be convenient if the spatial dimensions of the input and output are the same. For example, the channel dimension at one output pixel can hold the classification results for the input pixel at the same spatial position.

To achieve this, especially after the spatial dimensions are reduced by CNN layers, we can use another type of CNN layers that can increase (upsample) the spatial dimensions of intermediate feature maps. In this section, we will introduce transposed convolution, which is also called fractionally-strided convolution :cite:Dumoulin.Visin.2016, for reversing downsampling operations by the convolution.

```{.python .input} from mxnet import np, npx, init from mxnet.gluon import nn from d2l import mxnet as d2l

npx.set_np()

  2. ```{.python .input}
  3. #@tab pytorch
  4. import torch
  5. from torch import nn
  6. from d2l import torch as d2l

Basic Operation

Ignoring channels for now, let us begin with the basic transposed convolution operation with stride of 1 and no padding. Suppose that we are given a $n_h \times n_w$ input tensor and a $k_h \times k_w$ kernel. Sliding the kernel window with stride of 1 for $n_w$ times in each row and $n_h$ times in each column yields a total of $n_h n_w$ intermediate results. Each intermediate result is a $(n_h + k_h - 1) \times (n_w + k_w - 1)$ tensor that are initialized as zeros. To compute each intermediate tensor, each element in the input tensor is multiplied by the kernel so that the resulting $k_h \times k_w$ tensor replaces a portion in each intermediate tensor. Note that the position of the replaced portion in each intermediate tensor corresponds to the position of the element in the input tensor used for the computation. In the end, all the intermediate results are summed over to produce the output.

As an example, :numref:fig_trans_conv illustrates how transposed convolution with a $2\times 2$ kernel is computed for a $2\times 2$ input tensor.

Transposed convolution with a $2\times 2$ kernel. The shaded portions are a portion of an intermediate tensor as well as the input and kernel tensor elements used for the computation. :label:fig_trans_conv

We can (implement this basic transposed convolution operation) trans_conv for a input matrix X and a kernel matrix K.

```{.python .input}

@tab all

def trans_conv(X, K): h, w = K.shape Y = d2l.zeros((X.shape[0] + h - 1, X.shape[1] + w - 1)) for i in range(X.shape[0]): for j in range(X.shape[1]): Y[i: i + h, j: j + w] += X[i, j] * K return Y

  2. In contrast to the regular convolution (in :numref:`sec_conv_layer`) that *reduces* input elements
  3. via the kernel,
  4. the transposed convolution
  5. *broadcasts* input elements 
  6. via the kernel, thereby
  7. producing an output
  8. that is larger than the input.
  9. We can construct the input tensor `X` and the kernel tensor `K` from :numref:`fig_trans_conv` to [**validate the output of the above implementation**] of the basic two-dimensional transposed convolution operation.
  11. ```{.python .input}
  12. #@tab all
  13. X = d2l.tensor([[0.0, 1.0], [2.0, 3.0]])
  14. K = d2l.tensor([[0.0, 1.0], [2.0, 3.0]])
  15. trans_conv(X, K)

Alternatively, when the input X and kernel K are both four-dimensional tensors, we can [use high-level APIs to obtain the same results].

```{.python .input} X, K = X.reshape(1, 1, 2, 2), K.reshape(1, 1, 2, 2) tconv = nn.Conv2DTranspose(1, kernel_size=2) tconv.initialize(init.Constant(K)) tconv(X)

  2. ```{.python .input}
  3. #@tab pytorch
  4. X, K = X.reshape(1, 1, 2, 2), K.reshape(1, 1, 2, 2)
  5. tconv = nn.ConvTranspose2d(1, 1, kernel_size=2, bias=False)
  6. tconv.weight.data = K
  7. tconv(X)

[Padding, Strides, and Multiple Channels]

Different from in the regular convolution where padding is applied to input, it is applied to output in the transposed convolution. For example, when specifying the padding number on either side of the height and width as 1, the first and last rows and columns will be removed from the transposed convolution output.

```{.python .input} tconv = nn.Conv2DTranspose(1, kernel_size=2, padding=1) tconv.initialize(init.Constant(K)) tconv(X)

  2. ```{.python .input}
  3. #@tab pytorch
  4. tconv = nn.ConvTranspose2d(1, 1, kernel_size=2, padding=1, bias=False)
  5. tconv.weight.data = K
  6. tconv(X)

In the transposed convolution, strides are specified for intermediate results (thus output), not for input. Using the same input and kernel tensors from :numref:fig_trans_conv, changing the stride from 1 to 2 increases both the height and weight of intermediate tensors, hence the output tensor in :numref:fig_trans_conv_stride2.

Transposed convolution with a $2\times 2$ kernel with stride of 2. The shaded portions are a portion of an intermediate tensor as well as the input and kernel tensor elements used for the computation. :label:fig_trans_conv_stride2

The following code snippet can validate the transposed convolution output for stride of 2 in :numref:fig_trans_conv_stride2.

```{.python .input} tconv = nn.Conv2DTranspose(1, kernel_size=2, strides=2) tconv.initialize(init.Constant(K)) tconv(X)

  2. ```{.python .input}
  3. #@tab pytorch
  4. tconv = nn.ConvTranspose2d(1, 1, kernel_size=2, stride=2, bias=False)
  5. tconv.weight.data = K
  6. tconv(X)

For multiple input and output channels, the transposed convolution works in the same way as the regular convolution. Suppose that the input has $c_i$ channels, and that the transposed convolution assigns a $k_h\times k_w$ kernel tensor to each input channel. When multiple output channels are specified, we will have a $c_i\times k_h\times k_w$ kernel for each output channel.

As in all, if we feed $\mathsf{X}$ into a convolutional layer $f$ to output $\mathsf{Y}=f(\mathsf{X})$ and create a transposed convolutional layer $g$ with the same hyperparameters as $f$ except for the number of output channels being the number of channels in $\mathsf{X}$, then $g(Y)$ will have the same shape as $\mathsf{X}$. This can be illustrated in the following example.

```{.python .input} X = np.random.uniform(size=(1, 10, 16, 16)) conv = nn.Conv2D(20, kernel_size=5, padding=2, strides=3) tconv = nn.Conv2DTranspose(10, kernel_size=5, padding=2, strides=3) conv.initialize() tconv.initialize() tconv(conv(X)).shape == X.shape

  2. ```{.python .input}
  3. #@tab pytorch
  4. X = torch.rand(size=(1, 10, 16, 16))
  5. conv = nn.Conv2d(10, 20, kernel_size=5, padding=2, stride=3)
  6. tconv = nn.ConvTranspose2d(20, 10, kernel_size=5, padding=2, stride=3)
  7. tconv(conv(X)).shape == X.shape

[Connection to Matrix Transposition]

:label:subsec-connection-to-mat-transposition

The transposed convolution is named after the matrix transposition. To explain, let us first see how to implement convolutions using matrix multiplications. In the example below, we define a $3\times 3$ input X and a $2\times 2$ convolution kernel K, and then use the corr2d function to compute the convolution output Y.

```{.python .input}

@tab all

X = d2l.arange(9.0).reshape(3, 3) K = d2l.tensor([[1.0, 2.0], [3.0, 4.0]]) Y = d2l.corr2d(X, K) Y

  2. Next, we rewrite the convolution kernel `K` as
  3. a sparse weight matrix `W`
  4. containing a lot of zeros. 
  5. The shape of the weight matrix is ($4$, $9$),
  6. where the non-zero elements come from
  7. the convolution kernel `K`.
  9. ```{.python .input}
  10. #@tab all
  11. def kernel2matrix(K):
  12.     k, W = d2l.zeros(5), d2l.zeros((4, 9))
  13.     k[:2], k[3:5] = K[0, :], K[1, :]
  14.     W[0, :5], W[1, 1:6], W[2, 3:8], W[3, 4:] = k, k, k, k
  15.     return W
  17. W = kernel2matrix(K)
  18. W

Concatenate the input X row by row to get a vector of length 9. Then the matrix multiplication of W and the vectorized X gives a vector of length 4. After reshaping it, we can obtain the same result Y from the original convolution operation above: we just implemented convolutions using matrix multiplications.

```{.python .input}

@tab all

Y == d2l.matmul(W, d2l.reshape(X, -1)).reshape(2, 2)

  2. Likewise, we can implement transposed convolutions using
  3. matrix multiplications.
  4. In the following example,
  5. we take the $2 \times 2$ output `Y` from the above
  6. regular convolution
  7. as the input to the transposed convolution.
  8. To implement this operation by multiplying matrices,
  9. we only need to transpose the weight matrix `W`
  10. with the new shape $(9, 4)$.
  12. ```{.python .input}
  13. #@tab all
  14. Z = trans_conv(Y, K)
  15. Z == d2l.matmul(W.T, d2l.reshape(Y, -1)).reshape(3, 3)

Consider implementing the convolution by multiplying matrices. Given an input vector $\mathbf{x}$ and a weight matrix $\mathbf{W}$, the forward propagation function of the convolution can be implemented by multiplying its input with the weight matrix and outputting a vector $\mathbf{y}=\mathbf{W}\mathbf{x}$. Since backpropagation follows the chain rule and $\nabla_{\mathbf{x}}\mathbf{y}=\mathbf{W}^\top$, the backpropagation function of the convolution can be implemented by multiplying its input with the transposed weight matrix $\mathbf{W}^\top$. Therefore, the transposed convolutional layer can just exchange the forward propagation function and the backpropagation function of the convolutional layer: its forward propagation
and backpropagation functions multiply their input vector with $\mathbf{W}^\top$ and $\mathbf{W}$, respectively.

Summary

  • In contrast to the regular convolution that reduces input elements via the kernel, the transposed convolution broadcasts input elements via the kernel, thereby producing an output that is larger than the input.
  • If we feed $\mathsf{X}$ into a convolutional layer $f$ to output $\mathsf{Y}=f(\mathsf{X})$ and create a transposed convolutional layer $g$ with the same hyperparameters as $f$ except for the number of output channels being the number of channels in $\mathsf{X}$, then $g(Y)$ will have the same shape as $\mathsf{X}$.
  • We can implement convolutions using matrix multiplications. The transposed convolutional layer can just exchange the forward propagation function and the backpropagation function of the convolutional layer.

Exercises

  1. In :numref:subsec-connection-to-mat-transposition, the convolution input X and the transposed convolution output Z have the same shape. Do they have the same value? Why?
  2. Is it efficient to use matrix multiplications to implement convolutions? Why?

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