需求:数组转成树状结构
data: [{
label: '张大大',
children: [
{
label: '小亮',
children: [{ label: '小丽' }, { label: '大光' }]
}]
}],
数据:
const arr = [
{ id: '01', name: '张大大', pid: '', job: '项目经理' },
{ id: '02', name: '小亮', pid: '01', job: '产品leader' },
{ id: '03', name: '小美', pid: '01', job: 'UIleader' },
{ id: '04', name: '老马', pid: '01', job: '技术leader' },
{ id: '05', name: '老王', pid: '01', job: '测试leader' },
{ id: '06', name: '老李', pid: '01', job: '运维leader' },
{ id: '07', name: '小丽', pid: '02', job: '产品经理' },
{ id: '08', name: '大光', pid: '02', job: '产品经理' },
{ id: '09', name: '小高', pid: '03', job: 'UI设计师' },
{ id: '10', name: '小刘', pid: '04', job: '前端工程师' },
{ id: '11', name: '小华', pid: '04', job: '后端工程师' },
{ id: '12', name: '小李', pid: '04', job: '后端工程师' },
{ id: '13', name: '小赵', pid: '05', job: '测试工程师' },
{ id: '14', name: '小强', pid: '05', job: '测试工程师' },
{ id: '15', name: '小涛', pid: '06', job: '运维工程师' },
{ id: '16', name: '小才', pid: '07', job: '运维工程师' },
]
答案:
方法一
arr.forEach(item => {
// item.pid 为" "时 返回underfined
let parent = obj[item.pid]
if (parent) {
(parent.children || (parent.children = [])).push(item)
} else {
// 这里push的item是pid为undefined的数据
result.push(item)
}
})
console.log(result)
方法二:用递归函数
function filterArray(data, pid) {
var tree = []
var temp
for (var i = 0; i < data.length; i++) {
if (data[i].pid == pid) {
var obj = data[i]
temp = filterArray(data, data[i].id)
if (temp.length > 0) {
obj.children = temp
}
tree.push(obj)
}
}
return tree
}
console.log(filterArray(arr, ''))