1, 题目
反转一个单链表。
示例:
输入: 1->2->3->4->5->NULL输出: 5->4->3->2->1->NULL
进阶:
你可以迭代或递归地反转链表。你能否用两种方法解决这道题?
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/reverse-linked-list
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
2, 算法
object Solution {def reverseList(head: ListNode): ListNode = {val result = new ListNode()var current = headwhile (current != null) {val t = currentcurrent = current.nextt.next = nullt.next = result.nextresult.next = t}val x = result.nextresult.next = nullx}}
class Solution:def reverseList(self, head: ListNode) -> ListNode:result = ListNode()while head:t = headhead = head.nextt.next = Nonet.next = result.nextresult.next = thead = result.nextresult.next = Nonereturn head
