算法

deque

https://blog.csdn.net/devnn/article/details/82591349
https://blog.csdn.net/devnn/article/details/82716447

1. 验证是否为回文串

//方法来自力扣
public boolean validPalindromic(char[] charArray, int left, int right) {
    while (left < right) {
        if (charArray[left] != charArray[right]) {
            return false;
        }
        left++;
        right--;
    }
    return true;
}