- 两两交换链表中的节点
难度中等
给你一个链表,两两交换其中相邻的节点,并返回交换后链表的头节点。你必须在不修改节点内部的值的情况下完成本题(即,只能进行节点交换)。
示例 1:
输入:head = [1,2,3,4]
输出:[2,1,4,3]
示例 2:
输入:head = []
输出:[]
示例 3:
输入:head = [1]
输出:[1]
/*** Definition for singly-linked list.* public class ListNode {* int val;* ListNode next;* ListNode() {}* ListNode(int val) { this.val = val; }* ListNode(int val, ListNode next) { this.val = val; this.next = next; }* }*/class Solution {public ListNode swapPairs(ListNode head) {if(head == null || head.next == null){return head;}ListNode dummy = new ListNode(0);dummy.next = head.next;ListNode next = head.next;head.next = next.next;next.next = head;head.next = swapPairs(head.next);return dummy.next;}}
