方式一 Conut（*）+1

请问下如图所示数据表(test)中 查询出小红的分数(fenshu)排名的 sql语句怎么写?谢谢大佬~

想要计算排第几名就是计算比他分数高的有几个，再加上自身就好了。

select count(1)+1 as '排名'
  from test
  where fenshu>(select fenshu from test where name='小红')

MySQL实现排名并查询指定用户排名功能

表结构：

CREATE TABLE test.testsort (
id int(11) NOT NULL AUTO_INCREMENT,
uid int(11) DEFAULT 0 COMMENT ‘用户id’,
score decimal(10, 2) DEFAULT 0.00 COMMENT ‘分数’,
PRIMARY KEY (id)
)
ENGINE = INNODB
AUTO_INCREMENT = 1
CHARACTER SET utf8
COLLATE utf8_general_ci
COMMENT = ‘测试排序’
ROW_FORMAT = DYNAMIC;
思路：可以先排序，再对结果进行编号；也可以先查询结果，再排序编号。

说明：

@rownum := @rownum + 1 中 := 是赋值的作用，这句话的意思是先执行@rownum + 1，然后把值赋给@rownum；

(SELECT @rownum := 0) r 这句话的意思是设置rownum字段的初始值为0，即编号从1开始。

实现排名：
方法一：
SELECT
t.,
@rownum := @rownum + 1 AS rownum
FROM (SELECT
@rownum := 0) r,
(SELECT

FROM testsort
ORDER BY score DESC) AS t;

方法二：
SELECT
t.*,
@rownum := @rownum + 1 AS rownum
FROM (SELECT
@rownum := 0) r,
testsort AS t
ORDER BY t.score DESC;

结果：

查看指定用户排名：
方法一：
SELECT
b.
FROM (SELECT
t.,
@rownum := @rownum + 1 AS rownum
FROM (SELECT
@rownum := 0) r,
(SELECT
*
FROM testsort
ORDER BY score DESC) AS t) AS b
WHERE b.uid = 222;

方法二:
SELECT
b.
FROM (SELECT
t.,
@rownum := @rownum + 1 AS rownum
FROM (SELECT
@rownum := 0) r,
testsort AS t
ORDER BY t.score DESC) AS b
WHERE b.uid = 222;

结果：

实现并列排名（相同分数排名相同）：
SELECT
obj.uid,
obj.score,
CASE WHEN @rowtotal = obj.score THEN @rownum WHEN @rowtotal := obj.score THEN @rownum := @rownum + 1 WHEN @rowtotal = 0 THEN @rownum := @rownum + 1 END AS rownum
FROM (SELECT
uid,
score
FROM testsort
ORDER BY score DESC) AS obj,
(SELECT
@rownum := 0,
@rowtotal := NULL) r

查询指定用户并列排名:
SELECT
total.*
FROM (SELECT
obj.uid,
obj.score,
CASE WHEN @rowtotal = obj.score THEN @rownum WHEN @rowtotal := obj.score THEN @rownum := @rownum + 1 WHEN @rowtotal = 0 THEN @rownum := @rownum + 1 END AS rownum
FROM (SELECT
uid,
score
FROM testsort
ORDER BY score DESC) AS obj,
(SELECT
@rownum := 0,
@rowtotal := NULL) r) AS total
WHERE total.uid = 222;

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原文链接：https://blog.csdn.net/ML/article/details/80038133