给你一个正整数 n ,生成一个包含 1 到 n2 所有元素,且元素按顺时针顺序螺旋排列的 n x n 正方形矩阵 matrix 。
示例 1:
输入:n = 3
输出:[[1,2,3],[8,9,4],[7,6,5]]
示例 2:
输入:n = 1
输出:[[1]]
提示:
1 <= n <= 20
class Solution:def generateMatrix(self, n: int) -> List[List[int]]:matrix = [[1] * n for _ in range(n)]flag = [[False] * n for _ in range(n)]value = 1x, y = 0, 0while True:while flag[x][y] is False: # 向右打印matrix[x][y] = valueif value == n ** 2:return(matrix)value += 1flag[x][y] = Trueif y == n - 1:x += 1breakelse:if flag[x][y + 1] is False:y += 1elif flag[x + 1][y] is False:x += 1breakelse:breakwhile flag[x][y] is False: # 向下打印matrix[x][y] = valueif value == n ** 2:return(matrix)value += 1flag[x][y] = Trueif x == n - 1:y -= 1breakelse:if flag[x + 1][y] is False:x += 1elif flag[x][y - 1] is False:y -= 1breakelse:breakwhile flag[x][y] is False: # 向左打印matrix[x][y] = valueif value == n ** 2:return(matrix)value += 1flag[x][y] = Trueif y == 0:x -= 1breakelse:if flag[x][y - 1] is False:y -= 1elif flag[x - 1][y] is False:x -= 1breakelse:breakwhile flag[x][y] is False: # 向上打印matrix[x][y] = valueif value == n ** 2:return(matrix)value += 1flag[x][y] = Trueif x == 0:y += 1breakelse:if flag[x - 1][y] is False:x -= 1elif flag[x][y + 1] is False:y += 1breakelse:break
class Solution:def generateMatrix(self, n: int) -> List[List[int]]:l, r, t, b = 0, n - 1, 0, n - 1mat = [[0 for _ in range(n)] for _ in range(n)]num, tar = 1, n * nwhile num <= tar:for i in range(l, r + 1): # left to rightmat[t][i] = numnum += 1t += 1for i in range(t, b + 1): # top to bottommat[i][r] = numnum += 1r -= 1for i in range(r, l - 1, -1): # right to leftmat[b][i] = numnum += 1b -= 1for i in range(b, t - 1, -1): # bottom to topmat[i][l] = numnum += 1l += 1return mat
