场景描述
完成将 toChineseNum, 可以将数字转换成中文大写的表示,处理到万级别,例如 toChineseNum(12345),返回 一万二千三百四十五。
思路解析:
- 零到九的汉字索引数组
- 个十百千万的计量单位
- 数字转为字符串解析,每个十进制有单独的数字表示
- 对零的处理,重复多个零只读一个,后面无数字的省略零
- 对超出万计量的重新按照千百十的计量
const toChineseNum = (num) => {let dtext=['','十','百','千','万']let len=num.toString().lengthlet numArr=num.toString().split('')let numTxt=''const toT=(numIndex)=>{const arr=['零','一','二','三','四','五','六','七','八','九']return arr[numIndex]}for(let i=1;i<=len;i++){if(len>5&&i<(len-3)){if(i==(len-4)){numTxt+=numArr[i-1]==0?'':toT(numArr[i-1])numTxt+='万'}else{if((numArr[i-2]==0&&numArr[i-1]==0)||((numArr[i-1]==0)&&(numArr[len-5]==0)&&numArr[i]==0)){numTxt+=''}else{numTxt+=(((numArr[i-1]==0)&&(numArr[len-5]!=0))||(numArr[i]!=0&&numArr[i-1]==0))?'零':(toT(numArr[i-1])+dtext[len-i-4])}}}else{if((numArr[i-1]==0&&i==len)||(numArr[i]==0&&numArr[i-1]==0)){numTxt+=''}else{numTxt+=numArr[i-1]==0?'零':(toT(numArr[i-1])+dtext[len-i])}}}return numTxt}
