解法一:遍历 解法一:遍历遍历前半部分,与后半部分对应位置交换。 class Solution { public void reverseString(char[] s) { final int len = s.length; char temp; for (int i = 0; i < len / 2; ++i) { temp = s[i]; s[i] = s[len - i - 1]; s[len - i - 1] = temp; } }}