539. 最小时间差

解法一

现将时间格式转换为以分钟为单位的整数，排序后求最小差值，注意最大值和最小值之间的差有两种算法，其中一种要补上一天的时间1440分钟。

import java.util.Arrays;
import java.util.List;
class Solution {
    public int findMinDifference(List<String> timePoints) {
        int[] times = new int[timePoints.size()];
        String[] hourAndMinute = new String[2];
        for (int i = 0; i < timePoints.size(); ++i) {
            hourAndMinute = timePoints.get(i).split(":");
            times[i] = Integer.parseInt(hourAndMinute[0]) * 60 + Integer.parseInt(hourAndMinute[1]);
        }
        Arrays.sort(times);
        int min = times[0] - times[times.length - 1] + 1440;
        for (int i = 1; i < times.length; ++i) {
            min = Math.min(min, times[i] - times[i - 1]);
        }
        return min;
    }
}