Given a pattern and a string str, find if str follows the same pattern.

    Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.

    Example 1:

    1. Input: pattern = "abba", str = "dog cat cat dog"
    2. Output: true

    Example 2:

    Input:pattern = "abba", str = "dog cat cat fish"
    Output: false
    

    Example 3:

    Input: pattern = "aaaa", str = "dog cat cat dog"
    Output: false
    

    Example 4:

    Input: pattern = "abba", str = "dog dog dog dog"
    Output: false
    

    Notes:
    You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.

    Runtime: 0 ms, faster than 100.00% of C++ online submissions for Word Pattern.

    class Solution {
    public:
        bool wordPattern(string pattern, string str) {
            map<char, int> patternMap;
            map<string, int> wordMap;
            istringstream in(str);
            int i = 0, n = pattern.size();
            for (string word; in >> word; i++)
            {
                if (i == n || patternMap[pattern[i]] != wordMap[word])
                {
                    return false;
                }
                patternMap[pattern[i]] = wordMap[word] = i + 1;
            }
            return i == n;
        }
    };