Given a pattern
and a string str
, find if str
follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern
and a non-empty word in str
.
Example 1:
Input: pattern = "abba", str = "dog cat cat dog"
Output: true
Example 2:
Input:pattern = "abba", str = "dog cat cat fish"
Output: false
Example 3:
Input: pattern = "aaaa", str = "dog cat cat dog"
Output: false
Example 4:
Input: pattern = "abba", str = "dog dog dog dog"
Output: false
Notes:
You may assume pattern
contains only lowercase letters, and str
contains lowercase letters separated by a single space.
Runtime: 0 ms, faster than 100.00% of C++ online submissions for Word Pattern.
class Solution {
public:
bool wordPattern(string pattern, string str) {
map<char, int> patternMap;
map<string, int> wordMap;
istringstream in(str);
int i = 0, n = pattern.size();
for (string word; in >> word; i++)
{
if (i == n || patternMap[pattern[i]] != wordMap[word])
{
return false;
}
patternMap[pattern[i]] = wordMap[word] = i + 1;
}
return i == n;
}
};